Linear momentum and energy problem

In summary, Jane needs to swing across a river with a width of 50 meters while on a vine of length 40 meters and initially make an angle of 50 degrees with the vertical. She needs to have a minimum speed of 6.16 meters per second to just make it to the other side.
  • #1
cero39
4
0

Homework Statement



Jane, whose mass is 50 kg, needs to swing across a river having width D (50 m). She must swing into a wind with force F = 100 N while on a vine of length L (40 m) and initially making an angle theta of 50 degrees with the vertical. What minimum speed must Jane have to just make it to the other side?

m = 50kg, θ = 50, L = 40m, D = 50m, F = 110N.

Homework Equations


PE = mgh, KE = 1/2*m*v^2, W = F*d, p = m*v(?)


The Attempt at a Solution


Jane's energy has to be greater than that of the wind in order to get across the gap. So I found W_wind = 110N * 50m and subtracted that from Jane's potential energy. I found her height using h = L (1 - cosθ) = 14.29m. I then subtracted the wind's energy from that and deduced that the left over energy is from KE so I solved for v using KE = 1/2mv^2. The problem is, I don't think I did this right. This is in a chapter called linear momentum and collisions and I didn't use either in this problem. I'm studying for a test tomorrow and there's a good chance something like this will be on it. Was this even the right approach?
 
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  • #2
At what height does she end up at when she gets across the river? Your attempt assumes that she reaches the other side at the bottom of the swing.
 
  • #3
Hm... It doesn't say but in the picture there is an angle phi to the left of the vertical, on the other side of theta. So she does swing past the vertical but no information is given as to how far past or how high...
 
  • #4
You have to calculate where she ends up. You know she travels 50 meters horizontally, and you can calculate how far she travels horizontally as a function of theta, phi, and the length of the vine.
 
  • #5
Right so once I find the height I calculate the energy needed to go that high (m*g*h_2), add it to that of the wind(F*d), subtract from the potential energy at the first height (7002.1 J), and use that as my KE?
If so, I get 6.16 m/s as my answer.
 
  • #6
Sounds good.
 
  • #7
Great. Thank you.
 

What is linear momentum?

Linear momentum is a measure of an object's motion, specifically its mass times its velocity. It is a vector quantity, meaning it has both magnitude and direction.

What is the conservation of linear momentum?

The conservation of linear momentum states that in a closed system, the total linear momentum remains constant. This means that the total momentum before and after a collision or interaction is the same.

How is linear momentum different from energy?

Linear momentum and energy are both measures of motion, but they are not the same. Linear momentum depends on an object's mass and velocity, while energy depends on its mass, velocity, and position. Additionally, momentum is a vector quantity, while energy is a scalar quantity.

Can linear momentum be negative?

Yes, linear momentum can be negative. This occurs when the object is moving in the opposite direction of its chosen positive direction. For example, if the positive direction is to the right and an object is moving to the left, its momentum would be negative.

How is the principle of conservation of energy related to linear momentum?

The principle of conservation of energy and the conservation of linear momentum are related because they both involve the total amount of a physical quantity remaining constant in a closed system. In a collision or interaction, both energy and momentum must be conserved.

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