- #1

ainster31

- 158

- 1

What happens if I connect a capacitor to a DC battery of 10 volts? At this point, there is a constant voltage across the capacitor of 10V, right? Now what happens if I remove the wire connecting the battery to the capacitor? Isn't that an abrupt change of voltage because it drops from 10V to 0V?

Also, from diagram A, I notice that while voltage is continuous, the derivative of the voltage is not defined at one point. I know that the equation of the current is:

$$i=C\cdot \frac { dv }{ dt }$$

So what happens to the current in that instant where the derivative of voltage w.r.t. time is not defined (i.e. at the top of the corner)? Would current be undefined? Is that physically possible?