What Properties of Fourier Series Are Revealed by This Equation Transformation?

Click For Summary
SUMMARY

The discussion focuses on the properties of Fourier series as revealed by the transformation of a specific equation. The equation simplifies to $$\frac{\pi}{4}=\sum_{m=0}^\infty \frac{1}{2m+1}\sin\left(\frac{(2m+1)\pi}{2}\right)$$, highlighting the significance of sine values at odd half multiples of $$\pi$$. Participants emphasize the importance of understanding these sine values to fully grasp the implications of the series. This transformation showcases the convergence properties and the relationship between Fourier series and trigonometric functions.

PREREQUISITES
  • Understanding of Fourier series and their convergence properties
  • Knowledge of trigonometric functions, specifically sine values
  • Familiarity with mathematical series and summation notation
  • Basic algebraic manipulation skills for rearranging equations
NEXT STEPS
  • Explore the properties of sine functions at odd multiples of $$\pi$$
  • Study the convergence criteria for Fourier series
  • Learn about the implications of Fourier series in signal processing
  • Investigate the relationship between Fourier series and other mathematical series
USEFUL FOR

Mathematicians, physics students, and anyone interested in the analysis of Fourier series and their applications in various fields such as signal processing and harmonic analysis.

nacho-man
Messages
166
Reaction score
0
Is there some properties I should be aware of?

after making the relevant substitutions, I ended up with

$2 = 1 + \sum\nolimits_{m=0}^\infty \frac{4}{(2m+1)\pi}\sin(\frac{(2m+1)\pi}{2})$

but I can't get past this
 

Attachments

  • asdasd.png
    asdasd.png
    21.1 KB · Views: 103
Physics news on Phys.org
nacho said:
Is there some properties I should be aware of?

after making the relevant substitutions, I ended up with

$2 = 1 + \sum\nolimits_{m=0}^\infty \frac{4}{(2m+1)\pi}\sin(\frac{(2m+1)\pi}{2})$

but I can't get past this

Rearrange to:

$$\frac{\pi}{4}=\sum_{m=0}^\infty \frac{1}{2m+1}\sin\left(\frac{(2m+1)\pi}{2}\right)$$

and ask yourself what values does the sine of odd half multiples of $$\pi $$ take?

.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
28
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K