What self-induced emf appears in that coil?

[McAfee]

Homework Statement

The Attempt at a Solution

I now know the units are nWb. I'm just getting a little confused by answer.

((6.1mH)(7.3mA))/224turnes=.198795) (mH*mA)/turnes

So would that equal= 198.795 nWb?

 

[gneill]

I now know the units are nWb. I'm just getting a little confused by answer.

((6.1mH)(7.3mA))/224turnes=.198795) (mH*mA)/turnes

So would that equal= 198.795 nWb?

Why are you dividing by the number of turns? From the definition of mutual inductance,
$$M = \frac{\Phi_2}{I_1}$$