Calculating the EMF in the coil while the field is changing

  • Thread starter Thread starter Ly444999
  • Start date Start date
  • Tags Tags
    Coil Emf Field
Click For Summary

Homework Help Overview

The problem involves calculating the induced electromotive force (emf) in a coil with a specific number of turns and resistance, subjected to a changing magnetic field. The context is rooted in electromagnetic induction principles.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relevance of the angle used in the emf calculation, particularly questioning the use of cos 90 and its implications on the result. There is exploration of the angle's significance due to the geometry of the coil and the magnetic field orientation.

Discussion Status

The discussion is focused on clarifying the angle involved in the calculation and its effect on the induced emf. Some participants have provided insights regarding the angle's value and its relevance, while others are seeking further understanding of the underlying concepts.

Contextual Notes

Participants are navigating the implications of the angle in the context of the problem's geometry, with specific reference to the magnetic field's orientation relative to the coil's plane.

Ly444999
Messages
19
Reaction score
0

Homework Statement


A coil with 200 turns of wire is wrapped on an 18.0 cm square frame. Each turn has the same area, equal to that of the frame, and the total resistance of the coil is 2.0Ω . A uniform magnetic field is applied perpendicularly to the plane of the coil. If the field changes uniformly from 0 to 0.500 T in 0.80 s, find the magnitude of the induced emf in the coil while the field has changed

Homework Equations


emf =N* (Δ(BAcosθ) / Δt)

The Attempt at a Solution


I'm having trouble understanding the answer to the problem. In a solution to this question I seen, the answer is gotten from doing this calculation:
emf = [(200)*(0.500-0)*(0.18*0.18)*cos 90] / 0.80
and the answer equals to 4.10 V.
What I don't understand is why do you multiply by the cos 90?
cos 90 in degrees is 0 and in radians it is -0.4480736...
Doing the calculation without the cos 90 will get that answer, so why is it in the equation?
 
Physics news on Phys.org
Ly444999 said:
What I don't understand is why do you multiply by the cos 90?
You need to make sure that you're using the correct angle. Check your notes or text to see when the angle is used and what it is the angle between.

Ly444999 said:
cos 90 in degrees is 0 and in radians it is -0.4480736...
Although you will find that the actual angle involved won't be 90°, note that 90° is equivalent to ##\pi/2## radians, and they are in fact the same angle and have the same cosine value: zero.
 
gneill said:
You need to make sure that you're using the correct angle. Check your notes or text to see when the angle is used and what it is the angle between.
So would no angle at all be used in this case?
 
Ly444999 said:
So would no angle at all be used in this case?
There's an angle, but thanks to the particular geometry specified for the problem it has a value that doesn't affect the calculated result. You should make sure that you understand what that angle actually represents.
 
gneill said:
There's an angle, but thanks to the particular geometry specified for the problem it has a value that doesn't affect the calculated result. You should make sure that you understand what that angle actually represents.
I'm not sure if I'm following but, since the magnetic field is applied perpendicularly to the plane of the coil, the angle is actually 0 instead of 90?
 
Ly444999 said:
I'm not sure if I'm following but, since the magnetic field is applied perpendicularly to the plane of the coil, the angle is actually 0 instead of 90?
Yes.
 
gneill said:
Yes.
Thanks for your help!
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
8
Views
1K
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
Replies
7
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K