What speed will the ball hit the ground?

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SUMMARY

The discussion focuses on calculating the speed at which a ball will hit the ground, given its mass of 0.24 kg, an initial velocity of 20.0 m/s, and a gravitational potential energy of 70 J. The key equations used include kinetic energy (Ek = mv²/2) and gravitational potential energy (Eg = mgh). The final speed upon impact is determined to be 31.4 m/s, based on the conversion of potential energy into kinetic energy during the fall.

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A ball has a mass of 240g. (which would be 0.24kg?) is moving through the air at 20.0m/s with a gravitational potential energy of 70J. With what speed will the ball hit the ground.

Equations:

Ek=mv^2/2 (kinetic energy)
Eg=mgh (Gravitational potential energy)
Ek=mgxdisplacement (if you don't have velocity?)

I would appreciate ANY help...I don't get what I'm supposed to do.

P.S. the answer in the book says it should be 31.4m/s :)
 
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You assume that the groud is zero potential: Then the initian kinetic energy is T_i =1/2mv_i^2
And the initial potential energy is 70J the 70J is all being converted to kinetic energy when it falls so make your equation and solve it:
E_{initial}= 70J+T_i = E_{final}
 
Thank you :)
 

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