Why is my calculation for the determinant of a matrix incorrect?

  • Thread starter Thread starter ver_mathstats
  • Start date Start date
  • Tags Tags
    Determinant
Click For Summary

Homework Help Overview

The discussion revolves around the calculation of the determinant of a matrix, specifically addressing an incorrect computation and the properties of determinants. Participants explore the implications of matrix transposition and scalar multiplication on determinants.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the determinant using a specific formula but questions the validity of their result. Other participants raise questions about the properties of determinants, particularly regarding scalar multiplication and the relationship between a matrix and its transpose.

Discussion Status

Some participants have provided guidance on relevant properties of determinants, and there is an acknowledgment of the original poster's misunderstanding. Multiple interpretations of the determinant properties are being explored, but no explicit consensus has been reached.

Contextual Notes

There are references to specific properties of determinants that are deemed relevant, and some participants express confusion over the application of these properties in their calculations. The discussion includes a link to an external resource for further clarification.

ver_mathstats
Messages
258
Reaction score
21
Homework Statement
A=[a b c; d e f; g h i]

Suppose that det(A) = −5. Let B be another 3 × 3 matrix (not given here) with det(B) = 6. Find the determinant of each of the following matrices.

I found it for the other ones in the question except for:

What is the determinant of D=3(A^-1)(B^T)?
Relevant Equations
D=3(A^-1)(B^T)
I assumed that my calculation would be 3(-5^-1)(6) and I got the answer -18/5, however this is incorrect, I am unsure of where I am going wrong. I thought the determinant of a matrix is equal to the determinant of the transpose of the matrix so det(B)=6 would also be det(B^T)=6?

Thank you.
 
Physics news on Phys.org
What is the determinant of kA if A is a matrix and k s a constant?
 
ver_mathstats said:
Relevant Equations D=3(A^-1)(B^T)
What you wrote for a relevant equation isn't really relevant -- it's part of the problem statement.
Some equations that are relevant are shown in this wiki article, https://en.wikipedia.org/wiki/Determinant, in the Properties of the determinant section. The 2nd, 3rd, and 5th properties are especially relevant to your question.
 
Orodruin said:
What is the determinant of kA if A is a matrix and k s a constant?
Thank you for the reply, det(cA)=(c^n)det(A), I didn't realize this was the case, I ended up with the answer -162/5.
 
  • Like
Likes   Reactions: WWGD
Mark44 said:
What you wrote for a relevant equation isn't really relevant -- it's part of the problem statement.
Some equations that are relevant are shown in this wiki article, https://en.wikipedia.org/wiki/Determinant, in the Properties of the determinant section. The 2nd, 3rd, and 5th properties are especially relevant to your question.
Thank you for the reply, I used the properties, and realized where I went wrong, my answer is -162/5.
 
ver_mathstats said:
Thank you for the reply, det(cA)=(c^n)det(A), I didn't realize this was the case, I ended up with the answer -162/5.

It isn't needed but another way to remember this is we are dealing with n x n matrices here and determinants multiply so

##\det\big(c\mathbf A\big) = \det\big(c\mathbf I\mathbf A\big) = \det\big(c\mathbf I\big) \det\big(\mathbf A\big) = c^n \cdot \det\big(\mathbf A\big)##

where ##\det\big(c\mathbf I\big) ## is easy because it is a diagonal matrix with c on the diagonal -- the determinant of a diagonal matrix is always just the product of the diagonal components.
 
StoneTemplePython said:
It isn't needed but another way to remember this is we are dealing with n x n matrices here and determinants multiply so

##\det\big(c\mathbf A\big) = \det\big(c\mathbf I\mathbf A\big) = \det\big(c\mathbf I\big) \det\big(\mathbf A\big) = c^n \cdot \det\big(\mathbf A\big)##

where ##\det\big(c\mathbf I\big) ## is easy because it is a diagonal matrix with c on the diagonal -- the determinant of a diagonal matrix is always just the product of the diagonal components.
In fact, I often think of constants multiplying matrices as a diagonal matrix with all diagonal elements equal to that constant.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K