What values of F make the tension zero?

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    Tension Zero
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Homework Help Overview

The problem involves a system with two masses, where a horizontal force is applied to one mass on a frictionless surface. The discussion centers on determining the conditions under which the tension in the connecting cord becomes zero.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the applied force and the tension in the cord, questioning how the forces acting on the masses influence the tension. There is discussion about the conditions under which the tension becomes zero and the implications of different values of the applied force.

Discussion Status

Participants are actively engaging with the problem, sharing their reasoning and clarifying assumptions. Some have proposed that the applied force must counteract the weight of one of the masses for the tension to be zero, while others are examining the implications of specific force values.

Contextual Notes

There is some confusion regarding the forces acting on the masses and how they relate to the applied force. The discussion reflects varying interpretations of the problem setup and the role of the applied force in relation to the weights of the masses.

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Homework Statement


In the system shown in the figure below, a horizontal force x acts on the 7.00 kg object (m1). The horizontal surface is frictionless.
p5-37alt.gif

I solved the first part.
(a) For what values of Fx does the 4.00 kg object (m2) accelerate upward?
Fx> 39.24 N
I am totally confused on the second part.
(b) For what values of Fx is the tension in the cord zero?
Fx[tex]\leq[/tex] ?

Homework Equations


[tex]\sum[/tex]F=ma
(I don't think any other equations play a role.)

The Attempt at a Solution


I would think that for the tension to the zero, the Fx should be opposite value of the weight of m2. So -39.24 N. However, that's not right. I am confused about what forces are acting on the objects.
 
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The tension holds m2 back, preventing it from accelerating at g.
So when the tension is zero, m2 and m1 WILL accelerate at g.
Looks like Fx will have to be negative so it makes m1 keep up with m2.
 
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Okay, so if m1 is accelerating towards the end of the table at the same rate as g, then the tension will be zero? That makes sense...

So, m1*g=7*-9.81=-68.67.

EDIT:
Which is right, thanks for clearing that up for me.
 
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Which is the same as saying that if Fx= 0, there is no force supporting the weights and they fall freely- so no tension on the string.
 
Hm? If Fx=0, then the tension in the string is the same as the weight of m2, is it not?
 
Super - wasn't so tough after all!
 

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