The equation sin(kx) = 0 is solved by the values of x defined as x = n(pi)/k, where n is any integer. The additional term x = n(pi)/k + (pi)k/n introduced in the discussion is incorrect and does not apply to the solution of this equation. The correct formulation relies solely on the fundamental periodicity of the sine function, which dictates that kx must equal n(pi) for integer values of n.
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mrcheeses said:Homework Statement
sin(kx)=0 What describes the value of x.
Homework Equations
N/A
The Attempt at a Solution
I remember doing this last year but I forgot how to.
kx=n(pi)
x= n(pi)/k
x=n(pi)/k + (pi)k/n where n is any integar
Is this right?