What was the object's speed as it fell off the edge of the table?

Click For Summary
SUMMARY

The object, weighing 100 g, was pushed and released 1.60 m from the edge of a table, falling 0.900 m to the floor and landing 40.0 cm away from the edge. The coefficient of kinetic friction was 0.300, and the calculated speed of the object as it left the table was 0.935 m/s. An error in calculating the frictional force was identified, as the mass needed to be converted from grams to kilograms. The work-energy theorem or Newton's second law can be used to determine the initial speed of the object upon release.

PREREQUISITES
  • Understanding of kinematics and projectile motion
  • Familiarity with the work-energy theorem
  • Knowledge of Newton's second law of motion
  • Ability to convert units (grams to kilograms)
NEXT STEPS
  • Learn about the work-energy theorem in detail
  • Study Newton's second law and its applications in kinematics
  • Explore the concept of friction and its calculations in physics
  • Investigate projectile motion equations and their derivations
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and dynamics, as well as educators seeking to clarify concepts related to motion and forces.

notagenius08
Messages
11
Reaction score
0

Homework Statement



This homework problem is under the Nonuniform circular motion problem, but seems more like a elementary kinematics.

You push the 100 g object and release it 1.60 m from the table edge. Unfortunately, you push a little too hard. The object slides across, sails off the edge, falls 0.900 m to the floor, and lands 40.0 cm from the edge of the table.

If the coefficient of kinetic friction is 0.300, what was the object's speed as you released it?

Homework Equations


t=sqrt of 2*height/9
Fk=coeff of friction*m*a =n*coeff of fric.

The Attempt at a Solution



Figured velocity as object leaves table to be .935 m/s
and Fk=295N

I am stuck on what to do next, can't find v,a, or t.
 
Physics news on Phys.org
notagenius08 said:

Homework Statement



This homework problem is under the Nonuniform circular motion problem, but seems more like a elementary kinematics.

You push the 100 g object and release it 1.60 m from the table edge. Unfortunately, you push a little too hard. The object slides across, sails off the edge, falls 0.900 m to the floor, and lands 40.0 cm from the edge of the table.

If the coefficient of kinetic friction is 0.300, what was the object's speed as you released it?


Homework Equations


t=sqrt of 2*height/9
Fk=coeff of friction*m*a =n*coeff of fric.


The Attempt at a Solution



Figured velocity as object leaves table to be .935 m/s
and Fk=295N

I am stuck on what to do next, can't find v,a, or t.
Your velocity as the object leaves the table looks good, but you made an error in determining Fk, you forgot to convert grams to kg (100grams = 0.1kg). Now once you correct the value for the friction force, ther are a number of ways to determine the initial speed of the object at its release, by looking at the forces acting on the block after its release, while it is on the table. The easiest way is the use of the work-energy theorem, if you are familiar with that method; or else, Newton 2 and the kinematic equations will do it. Give it a try.
 
Finally solved it! Thanks for your help. Still don't understand why the book listed it under nonuniform circular motion...


Thanks again.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 20 ·
Replies
20
Views
5K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K