What Was the Speed of the SUV Before the Collision in Phystown?

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SUMMARY

The collision analysis in Phystown involves a 1000 kg Toyota traveling at 65 km/h westward colliding with a 3000 kg SUV moving north. Post-collision, the wreckage moves at 45 km/h. To determine the SUV's speed before the collision, the conservation of momentum equation, mv1 + mv2 = v(m1 + m2), is applied. It is essential to analyze the momentum components separately due to the differing directions of the vehicles.

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Hannahj1
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Homework Statement


A collision in Phystown is being analyzed by the O.P.P. accident analysis team. A 1000 kg Toyota known to be moving at 65 km/h [W] collided at an intersection with a 3000 kg SUV moving [N]. After the collision, the two vehicles "stuck" together and the police estimate that immediately after impact the Toyota-SUV wreckage moved at 45 km/h. Based on this information, what was the speed of the SUV before the collision?

Homework Equations


mv1 + mv2 = v (m1 +m2)

The Attempt at a Solution


I just plugged in values into the equation that i was given from the question...
(1000)(-18.1) + 3000v2 = 12.5 (4000) -> i made E and N positive

I was just wondering if i did this right! should i do components since i have directions in y and x directions? Thank you!
 
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Hannahj1 said:
should i do components since i have directions in y and x directions?
You certainly should consider the components. You cannot add momenta that are in different directions.
Apply conservation of momentum in each of the two directions separately.
 

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