What will be ##\int_{v'}\vec \nabla_{v'}(1/R)dv'##

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Homework Help Overview

The discussion revolves around evaluating the integral ##\int_{v'}\vec \nabla_{v'}(1/R)dv'##, where ##R## is defined as the distance between two points represented by vectors ##\vec r## and ##\vec r'##. Participants are exploring the implications of vector calculus theorems and the setup of the problem in a spherical volume context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to relate the volume integral to a surface integral and are discussing the implications of the vector theorem. There are questions about the correctness of their manipulations and the assumptions regarding the spherical symmetry of the problem.

Discussion Status

The discussion is ongoing, with participants providing insights and seeking clarification on specific aspects of the integral. Some have suggested potential simplifications and connections to known theorems, while others are grappling with the complexities introduced by the variable unit vector in the integral.

Contextual Notes

There are references to constraints such as the fixed nature of the vector ##\vec r## and the behavior of the unit vector ##\hat r_s## during integration. Participants are also considering the implications of their findings in relation to concepts from electromagnetism.

Apashanka
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Homework Statement
What will be ##\int_{v'}\vec \nabla_{v'}(1/R)dv##
Relevant Equations
if the source be represented by the vector ##\vec r'## and another point of interest be ##\vec r## where ##\vec R=\vec r-\vec r'## with respect to a fixed origin,
Now from vector theorem ##\nabla_r'(1/R)=\frac{\hat R}{R^2}##
Now what will be ##\int_v'\nabla_r'(1/R)dv'## over a spherical volume....can anyone please help me out??
Problem Statement: What will be ##\int_{v'}\vec \nabla_{v'}(1/R)dv##
Relevant Equations: if the source be represented by the vector ##\vec r'## and another point of interest be ##\vec r## where ##\vec R=\vec r-\vec r'## with respect to a fixed origin,
Now from vector theorem ##\nabla_r'(1/R)=\frac{\hat R}{R^2}##
Now what will be ##\int_v'\nabla_r'(1/R)dv'## over a spherical volume...can anyone please help me out??

if the source be represented by the vector ##\vec r'## and another point of interest be ##\vec r## where ##\vec R=\vec r-\vec r'## with respect to a fixed origin,
Now from vector theorem ##\vec \nabla_{r'}(1/R)=\frac{\hat R}{R^2}##
Now what will be ##\int_{v'}\vec \nabla_{r'}(1/R)dv'## over a spherical volume...can anyone please help me out??
 
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Apashanka said:
Problem Statement: What will be ##\int_{v'}\vec \nabla_{v'}(1/R)dv##
Relevant Equations: if the source be represented by the vector ##\vec r'## and another point of interest be ##\vec r## where ##\vec R=\vec r-\vec r'## with respect to a fixed origin,
Now from vector theorem ##\nabla_r'(1/R)=\frac{\hat R}{R^2}##
Now what will be ##\int_v'\nabla_r'(1/R)dv'## over a spherical volume...can anyone please help me out??

Problem Statement: What will be ##\int_{v'}\vec \nabla_{v'}(1/R)dv##
Relevant Equations: if the source be represented by the vector ##\vec r'## and another point of interest be ##\vec r## where ##\vec R=\vec r-\vec r'## with respect to a fixed origin,
Now from vector theorem ##\nabla_r'(1/R)=\frac{\hat R}{R^2}##
Now what will be ##\int_v'\nabla_r'(1/R)dv'## over a spherical volume...can anyone please help me out??

if the source be represented by the vector ##\vec r'## and another point of interest be ##\vec r## where ##\vec R=\vec r-\vec r'## with respect to a fixed origin,
Now from vector theorem ##\vec \nabla_{r'}(1/R)=\frac{\hat R}{R^2}##
Now what will be ##\int_{v'}\vec \nabla_{r'}(1/R)dv'## over a spherical volume...can anyone please help me out??
The volume integral is written in terms of surface integral ##\int_s(1/R)\vec ds'##
##R=√[(\vec r-\vec r')•(\vec r-\vec r')]=√(r^2+r'^2-2r•r')=r'√(1+\frac{r^2}{r'^2}-2r•r'/r'^2)## for large ##r' ,R=r'##
##\int_s(1/r')r'^2sin\theta d\theta d\phi\hat r'=4\pi r'##
Is it correct??
 
Apashanka said:
The volume integral is written in terms of surface integral ##\int_s(1/R)\vec ds'##
##R=√[(\vec r-\vec r')•(\vec r-\vec r')]=√(r^2+r'^2-2r•r')=r'√(1+\frac{r^2}{r'^2}-2r•r'/r'^2)## for large ##r' ,R=r'##
##\int_s(1/r')r'^2sin\theta d\theta d\phi\hat r'=4\pi r'##
Is it correct??
The volume integral is having an ans. ##\int_{v'}\vec \nabla_{r'}(1/R)dv'=\frac{4\pi}{3}\vec r## over a large spherical volume,where ##\vec R=\vec r-\vec r'## is with respect to the origin coinciding with the centre is the sphere.
Can anyone please help me out in proving this...
 
Okay I have made a schematic diagram
IMG_20190512_213054.jpg

##\vec r## is fixed,##\vec R=\vec r-\vec r'##
now ##\int_{v'}\vec \nabla_{r'}(1/R)dv'=\int_{s'}(1/R)\vec ds'## is done over a spherical surface having radius ##r_s## then it reduces to ##\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\phi)}r_s^2sin\theta d\theta d\omega\hat r_s=2πr_s\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\phi)}sin\theta d\theta(\vec r-\vec R) ## where ##\omega## is the azimuth 0 to 2π ,##\theta=0## to ##\pi##.
Can anyone will give any hints how to deal with such type of integrals??
Note:within the integral ##\vec R=\vec r-\vec r_s## has it's tail at the surface of the sphere
 
Last edited:
Apashanka said:
Okay I have made a schematic diagram
View attachment 243456
##\vec r## is fixed,##\vec R=\vec r-\vec r'##
now ##\int_{v'}\vec \nabla_{r'}(1/R)dv'=\int_{s'}(1/R)\vec ds'## is done over a spherical surface having radius ##r_s## then it reduces to ##\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\phi)}r_s^2sin\theta d\theta d\omega\hat r_s=2πr_s\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\phi)}sin\theta d\theta(\vec r-\vec R) ## where ##\omega## is the azimuth 0 to 2π ,##\theta=0## to ##\pi##.
Can anyone will give any hints how to deal with such type of integrals??
Note:within the integral ##\vec R=\vec r-\vec r_s## has it's tail at the surface of the sphere

This is similar to the integration in the shell theorem, which you may have encountered. E.g:

http://hyperphysics.phy-astr.gsu.edu/hbase/Mechanics/sphshell.html#wtls
 
@PeroK
Okk ,then in that case the integral reduces to
##\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\theta)}r_s^2sin\theta d\theta d\omega\hat r_s=2πr_s\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\theta)}sin\theta d\theta(\vec r-\vec R)=4\pi\vec r-\int_s2\pi r_s\frac{\vec R}{r_s^2+r^2-2rr_scos(\theta)}sin\theta d\theta##
The problem here is within the integral there is ##\hat r_s## which is not constt. throughout the integration
 
Apashanka said:
@PeroK
Okk ,then in that case the integral reduces to
##\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\theta)}r_s^2sin\theta d\theta d\omega\hat r_s=2πr_s\int_{s'}\frac{1}{r_s^2+r^2-2rr_scos(\theta)}sin\theta d\theta(\vec r-\vec R)=4\pi\vec r-\int_s2\pi r_s\frac{\vec R}{r_s^2+r^2-2rr_scos(\theta)}sin\theta d\theta##
The problem here is within the integral there is ##\hat r_s## which is not constt. throughout the integration
The link I gave you shows a technique for tackling that.
 
PS if you have studied electromagnetism then a quick way is to find a charged sphere that generates the same integral for the electric field.
 
PeroK said:
PS if you have studied electromagnetism then a quick way is to find a charged sphere that generates the same integral for the electric field.
I understood this but the problem is how to tackle the unit vector ##\hat r_s## within the integral which is not constt. ,##r_s## is the radius of the sphere of integration
 
  • #10
Apashanka said:
I understood this but the problem is how to tackle the unit vector ##\hat r_s## within the integral which is not constt. ,##r_s## is the radius of the sphere of integration
IMG_20190513_114747.jpg

Our integration is ##\int_s(1/R)\vec ds=\int_s(1/R)r_s^2sin\theta d\theta d\phi \hat r_s,##
##R=√(r^2+r_s^2-2rr_scos\theta)##
##\hat r_s=(\vec r-\vec R)/r_s##
Putting these it reduces to ##2\pi r_s \int_s[\frac{\vec r}{R}-\hat R]sin\theta d\theta##
Now since ##\vec r## is constt. the first part is solvable but how to do the second part ??
 
  • #11
Okay I am asking for this type of integrals is due to ,I have came across this in the following snap of a paper by @Nick Kaiser
IMG_20190513_205158.jpg

In deriving this equation 8 from eq. 6 I think this integral will come in way for the term in the RHS containing ##\bar n##.Will anyone please help me out??or any idea in deriving eq.8 from eq.6...
 

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