- #1

AxM=Fam

- 8

- 0

2. K=8.988X10^9 N(m^2/c^2)

Fc= K(qs qd/r^2sd)(direction rsd)

I believe this is the electrostatic force formula? s=source d=detector.

3. This is my attempt at the problem.

Fc=(K)(3.00X10^-6C)(2.50X10^-9C)/(2.5625X10^-4 m^2) [.624695i+.780869j]

The 2.50X10^-9C was a negative to begin with but I redistributed the negative to the i and j hat direction to make them positive.

|Fcsd|=.26306N

θ=Tan^-1(.780869/.624695)=51.3degrees

I cannot figure out how to get the acceleration of this electron?

Do I use F=ma

.26306N/(9.109X10^-31 kg) = 2.89X10^29 m/s^2

I am probably using the wrong formula to begin with can I please get some help with this.