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What will be the horizontal acceleration

  • Thread starter JaZZyCooL
  • Start date
  • #1
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Homework Statement


a 4.00-kg block is sliding up the plane on a 30 degree incline. If the coefficient of kinetic friction between the block and the inline is .700. What will be the acceleration of the block if a 50-N horizontal force pushes on the block?

Homework Equations



50 - mgsin(30) - Uk*mg*cos(30) = ma

The Attempt at a Solution


[/B]
I am getting answer 6.65 something whereas the correct answer is 4.40 m/s.
I suck at this topic. This is the weakest point I would appreciate your help.
 
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Answers and Replies

  • #2
berkeman
Mentor
56,611
6,510

Homework Statement


a 4.00-kg block is sliding up the plane on a 30 degree incline. If the coefficient of kinetic friction between the block and the inline is .700. What will be the acceleration of the block if a 50-N horizontal force pushes on the block?

Homework Equations



50 - mgsin(30) - Uk*mg*cos(30) = ma

The Attempt at a Solution


[/B]
I am getting answer 6.65 something whereas the correct answer is 4.40 m/s.
I suck at this topic. This is the weakest point I would appreciate your help.
It seems like your setup is close. can you post all of your work so we can check it?
 
  • #3
7
0
It seems like your setup is close. can you post all of your work so we can check it?
50 - 4.0*9.8*sin(30)-4.0*0.7*9.8*cos(30) = 50 - 23.76 = 26.64
26.64/4.00 = 6.56 m/s^2
 
  • #4
TSny
Homework Helper
Gold Member
12,300
2,794
50 - mgsin(30) - Uk*mg*cos(30) = ma
Looks like you've worked the problem for the case where the 50 N force acts parallel to the incline. But the force is acting horizontally.
 
  • #5
7
0
So what will be the equation if the force is acting horizontal?
 
  • #6
TSny
Homework Helper
Gold Member
12,300
2,794
When you dealt with the weight mg, you broke it into components parallel and perpendicular to the slope. Do the same for the 50 N force.
 

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