What will be the horizontal acceleration

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Homework Help Overview

The discussion revolves around a physics problem involving a block sliding up a 30-degree incline, with a focus on calculating the horizontal acceleration when a horizontal force is applied. The problem includes considerations of kinetic friction and the forces acting on the block.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are examining the setup of the problem, particularly the application of forces and the direction of the horizontal force. There is a focus on breaking down forces into components and checking the calculations provided by the original poster.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's calculations and encouraging them to share their work for further examination. There is an acknowledgment of a potential misunderstanding regarding the direction of the applied force.

Contextual Notes

Participants are questioning the assumptions made about the direction of the applied force and its impact on the calculations. There is a mention of the original poster feeling uncertain about their understanding of the topic.

JaZZyCooL
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Homework Statement


a 4.00-kg block is sliding up the plane on a 30 degree incline. If the coefficient of kinetic friction between the block and the inline is .700. What will be the acceleration of the block if a 50-N horizontal force pushes on the block?

Homework Equations



50 - mgsin(30) - Uk*mg*cos(30) = ma

The Attempt at a Solution


[/B]
I am getting answer 6.65 something whereas the correct answer is 4.40 m/s.
I suck at this topic. This is the weakest point I would appreciate your help.
 
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JaZZyCooL said:

Homework Statement


a 4.00-kg block is sliding up the plane on a 30 degree incline. If the coefficient of kinetic friction between the block and the inline is .700. What will be the acceleration of the block if a 50-N horizontal force pushes on the block?

Homework Equations



50 - mgsin(30) - Uk*mg*cos(30) = ma

The Attempt at a Solution


[/B]
I am getting answer 6.65 something whereas the correct answer is 4.40 m/s.
I suck at this topic. This is the weakest point I would appreciate your help.

It seems like your setup is close. can you post all of your work so we can check it?
 
berkeman said:
It seems like your setup is close. can you post all of your work so we can check it?

50 - 4.0*9.8*sin(30)-4.0*0.7*9.8*cos(30) = 50 - 23.76 = 26.64
26.64/4.00 = 6.56 m/s^2
 
JaZZyCooL said:
50 - mgsin(30) - Uk*mg*cos(30) = ma
Looks like you've worked the problem for the case where the 50 N force acts parallel to the incline. But the force is acting horizontally.
 
So what will be the equation if the force is acting horizontal?
 
When you dealt with the weight mg, you broke it into components parallel and perpendicular to the slope. Do the same for the 50 N force.
 

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