1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Whats normal force at top/bottom of loop

  1. Mar 10, 2012 #1
    1. The problem statement, all variables and given/known data
    The small mass m sliding without friction along the looped track shown in the figure is to remain on the track at all times, even at the very top of the loop of radius r.

    http://session.masteringphysics.com/problemAsset/1057653/6/GIANCOLI.ch08.p090.jpg

    A)In terms of the given quantities, determine the minimum release height h.
    B)If the actual release height is 3h, calculate the normal force exerted by the track at the bottom of the loop.
    C)f the actual release height is 3h, calculate the normal force exerted by the track at the top of the loop.

    3. The attempt at a solution
    A)i was easily able to solve part A, i got 2.5r
    B)for this i started with energy conservation. i have that the potential energy at the beginning is equal to the kinetic energy at the bottom (3mgh=1/2mv^2, the potential energy being 3mgh because the starting height is 3h). i calculated the velocity to b v^2=6gh, which i then plugged into my centripetal force equation (ƩF=mv^2/r). N-mg=6mgh+mg, solving for N i get N=mg(6h+1/r), which is incorrect, im instructed that the answer does not depend on height.
     
  2. jcsd
  3. Mar 10, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    welcome to pf!

    hi bfusco! welcome to pf! :smile:
    how did that h survive? :confused:

    i thought you found what h was?​
     
  4. Mar 10, 2012 #3
    Re: welcome to pf!

    thank you tiny tim,

    hm...you make a good point i guess thats what happens when you stare at a board for hours, you miss the little things. lol im going to give that a try.
     
  5. Mar 10, 2012 #4
    hahahahaha it worked....i feel stupid right now. thank you for your help tiny tim
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook