What's the use of density here?

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Thread moved from the technical forums, so no Homework Template is shown
Pressure initial: 95 kPa
Final pressure: 190 kPa
Change in enthalpy: -2.96 kJ
Initial volume: 0.045 cu.meter
Density: 1.11 kg/cu.meter
pV=c
 
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Chestermiller said:
Is there some sort of problem statement here?

Oh. Sorry...
The problem is "What is the change in internal energy of ethane
 
Chestermiller said:
What are your thoughts on this?

I don't think it has any use.

W=pVln(P1/P2)
W=(95)(0.045)ln(95/190)
W=-2.96 kJ
Then,
Using : ΔU=Q-W
=-2.96kJ - (-2.96kJ)
=0 kJ

But I'm not sure about it
 
Are you sure they said pV=c? Because, if that's so, then ##\Delta (pV)=0##, which means that ##\Delta U=\Delta H-\Delta (pV)=\Delta H##. That would suggest non-ideal gas behavior. Are you currently learning about non-ideal gas behavior?

Do they give any indication of which state the density refers to, initial or final? Are there additional parts to this problem statement?
 
yeah they only said pV=constant. The density is on the Initial.
 
turtleGuy said:
yeah they only said pV=constant. The density is on the Initial.
pV being constant means that ##\Delta U=\Delta H##. But, if these both are not equal to zero, that means that the behavior is inconsistent with the behavior of an ideal gas. So either, the gas is behaving non-ideally or there is inconsistency in the problem statement. So I ask again, are you currently learning about the behavior of non-ideal gases, or are you only covering ideal gases now?