What's wrong with my algebraic expression?

  • Thread starter Thread starter Terrell
  • Start date Start date
  • Tags Tags
    Expression
Click For Summary
The discussion revolves around finding the demand and revenue functions for a store selling DVD burners, where a $10 rebate increases sales by 20 units weekly. The initial expression provided for revenue, R(x) = ($350-$10x)(200+20x), is debated, particularly regarding the interpretation of the demand function and the variable 'x'. Clarification is needed on how to define 'x' and differentiate between price and demand, as they are not the same. Participants emphasize that the demand function should be expressed as a function of price, with linear assumptions based on the given data. The conversation highlights the importance of correctly interpreting algebraic expressions in the context of market dynamics.
Terrell
Messages
316
Reaction score
26
Mentor note: moved to homework forum

A store has been selling 200 DVD burners a week at $350 each. A market survey indicates that for each $10 rebate offered to buyers, the number of units sold will increase by 20 a week. Find the demand function and the revenue function. How large a rebate should the store offer to maximize its revenue?

my expression: R(x) = ($350-$10x)(200+20x)
 
Last edited by a moderator:
Physics news on Phys.org
Terrell said:
A store has been selling 200 DVD burners a week at $350 each. A market survey indicates that for each $10 rebate offered to buyers, the number of units sold will increase by 20 a week. Find the demand function and the revenue function. How large a rebate should the store offer to maximize its revenue?

my expression: R(x) = ($350-$10x)(200+20x)
What did you get for the demand function?
 
Mark44 said:
What did you get for the demand function?
according to my textbook, demand function is also the price function... so i think that should be the ($350-$10x) part of the expression...?
 
Terrell said:
according to my textbook, demand function is also the price function...
I think you might be misinterpreting what the book is saying. Price and demand are two different things. Usually the demand is written as a function of the price, p.

According to your first post, when p = 350, the demand d will be 200. And when the price is decreased by $10, the demand is forecast to be 220.
Assuming that demand is a linear function of price, you should be able to write the demand function from that information.
Terrell said:
so i think that should be the ($350-$10x) part of the expression...?
 
Terrell said:
Mentor note: moved to homework forum

A store has been selling 200 DVD burners a week at $350 each. A market survey indicates that for each $10 rebate offered to buyers, the number of units sold will increase by 20 a week. Find the demand function and the revenue function. How large a rebate should the store offer to maximize its revenue?

my expression: R(x) = ($350-$10x)(200+20x)

Why do you think your expression is wrong? Aside from failing to define what you mean by 'x', it looks OK to me, provided that you are extra careful about what 'x' actually means.

Now: what about the rest of the problem?
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
7K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 61 ·
3
Replies
61
Views
9K
  • · Replies 22 ·
Replies
22
Views
31K
  • · Replies 28 ·
Replies
28
Views
10K
  • · Replies 11 ·
Replies
11
Views
3K