Undergrad When can I commute the 4-gradient and the "space-time" integral?

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The discussion centers on the ability to commute a partial derivative with an integral involving an exponential function. It is established that the integral and derivative can be interchanged under certain conditions, specifically when the integrand behaves well. The example provided demonstrates that both approaches yield the same result, confirming the validity of commuting the operations. The reference to Leibniz's integral rule supports this conclusion, emphasizing the conditions under which differentiation and integration can be interchanged. Overall, the ability to commute the integral and partial derivative is affirmed in this context.
tannhaus
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I do not know how to procceed in a situation where I have a 4-gradient and a space-time integral.
Let's say I have the following situation

$$I = \dfrac{\partial}{\partial x^{\alpha}}\int e^{k_{\mu}x^{\mu}} \;d^4k$$

Would I be able to commute the integral and the partial derivative? If so, why is that? In the same line of thought, in the situation I'm able to commute, would the result of this be

$$I = \int k_{\alpha}e^{k_{\mu}x^{\mu}}\;d^4k$$

Thanks in advance!
 
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tannhaus said:
Would I be able to commute the integral and the partial derivative? If so, why is that?
Since:$$e^{k_{\mu}x^{\mu}}=e^{k_{0}x^{0}}e^{k_{1}x^{1}}e^{k_{2}x^{2}}e^{k_{3}x^{3}}$$you only need to consider the behavior of a single integral of the form ##\int e^{kx}dk##. So compare:$$\frac{d}{dx}\left\{ \int e^{kx}dk\right\} =\frac{d}{dx}\left\{ \frac{e^{kx}}{x}\right\} =\frac{e^{kx}\left(kx-1\right)}{x^{2}}$$to:$$\int\left\{ \frac{d}{dx}\left(e^{kx}\right)\right\} dk=\int\left\{ ke^{kx}\right\} dk=\frac{e^{kx}\left(kx-1\right)}{x^{2}}$$These are equal so it's clearly OK to commute differentiation and integration in your situation.
 

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