When Does the Equation Ax=B Have Unique, Multiple, or No Solutions?

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SUMMARY

The equation Ax = B has a unique solution when matrix A is non-singular, meaning its determinant (det(A)) is not equal to zero. If A is full rank, there is exactly one solution. When A is rank-deficient and vector B lies within the column space of A, there are infinitely many solutions. Conversely, if A is rank-deficient and B lies in the left-nullspace of A, there is no solution. Understanding these conditions is crucial for solving linear equations effectively.

PREREQUISITES
  • Linear algebra concepts, specifically matrix rank and determinants.
  • Understanding of eigenvalues and their relation to matrix properties.
  • Familiarity with the column space and left-nullspace of matrices.
  • Knowledge of the implications of singular vs. non-singular matrices.
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  • Study the properties of determinants in matrix theory.
  • Learn about matrix rank and its implications for solutions to linear equations.
  • Explore the concepts of column space and left-nullspace in linear algebra.
  • Investigate the relationship between eigenvalues and matrix singularity.
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Students and professionals in mathematics, engineering, and computer science who are dealing with linear equations and matrix theory, particularly those focusing on solving systems of equations.

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i need to remember when does Ax=B has a unique solution, more than one, and no solution?

i think that it has a unique solution when A is non singular i.e when det(A) isn't equal zero (at least that's what's written in my notes).

what about more than one solution, what conditipns should be met for either of A,x or b (also for no solution).

i guess that when A isn't non singular then the equation doesn't have solution but I am not sure, forgot about this.
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There is a unique solution if A is full rank, infinite solutions if A is rank-deficient and b lies in the column space (or range) of A, and no solution if A is rank-deficient and b lies in the left-nullspace of A.

The determinant of a matrix is the product of its eigenvalues. A rank-deficient matrix would have some of its eigenvalues equal zero, thus the determinant equals zero. Any matrix A with det(A) = 0 would therefore admit either infinite number of solutions or no solution for Ax = b.
 

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