When does the Frullani type integral hold equality?

  • Context: Graduate 
  • Thread starter Thread starter mhill
  • Start date Start date
  • Tags Tags
    Integral Type
Click For Summary

Discussion Overview

The discussion revolves around the conditions under which a specific Frullani type integral holds equality. Participants explore the formulation of the integral and seek generalizations, focusing on the functions involved and their convergence properties.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant asks under what conditions the equality holds for the integral involving functions f and g.
  • Another participant seeks clarification on the notation, questioning if G(t) refers to the integral of g(t).
  • A participant confirms the intent to refer to the integral of g(t) and expresses difficulty in finding generalizations for the integral while inquiring about the conditions for convergence.
  • Another participant introduces the generalized mean value theorem, suggesting it may relate to the integral in question by indicating a relationship between the differences of f and g and their derivatives.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the conditions for equality in the integral, and multiple viewpoints regarding the functions and their properties remain present.

Contextual Notes

There are unresolved aspects regarding the definitions of the functions f and g, as well as the conditions necessary for the convergence of the integral.

mhill
Messages
180
Reaction score
1
under what condition the does the equality hold ?

[tex]\int_{0}^{\infty} dt \frac{ f(at)-f(bt)}{g(t)}= (G(b)-G(a))(f(0)-f(\infty))[/tex]

and [tex]\int dt g(t)[/tex]
 
Physics news on Phys.org
Did you mean to say
[tex]G(t)= \int dt g(t)[/tex]
in your last line?
 
yes i meant the integral of g(t) ,i have been looking for generalizations of this integral but without any luck , under that condition can define g(t) and f(at) f(bt) so the integral above converge ?? thank
 
The generalized mean value theorem says that if f and g are differentiable on (a, b) and continuous on [a, b], then there exist c in (a, b) such that
[tex]\frac{f(b)- f(a)}{g(b)- g(a)}= \frac{f'(c)}{g'(c)}[/tex]

That looks like an integral version to me.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K