When Does the Wave Reach Maximum Displacement?

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SUMMARY

The wave displacement described by the equation Y(x, t) = 0.35 (m) Sin (6x - 30t) reaches its maximum displacement when the argument of the sine function equals π/2. This occurs at the specific time of 0.04 seconds, leading to the equation π/2 = 6x - 30(0.04). The horizontal compression is indicated by the coefficient of x, which affects the position of maximum displacement but does not alter the fundamental property that sine reaches its peak at π/2. The vertical compression is determined by the amplitude of 0.35 meters.

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Homework Statement


The displacement of the wave traveling in + x direction is: Y(x, t) = 0.35 (m) Sin (6x- 30t); where x is in meter and t is in second.

If the wave reaches its maximum displacement after 0.04 sec,
what is the value of x corresponding to y (max).


Homework Equations


Y(x,t)=Asin(kx-wt)


The Attempt at a Solution


Well I know that with a "standard" sin curve, it reaches a maximum when x=pi/2. However, doesn't this particular displacement equation Y(x, t) = 0.35 (m) Sin (6x- 30t) have a horizontal compression (ie. indicated by what's in the brackets, 6x-30t) so that it's maximum (ie. max displacement) wouldn't occur at 90 degrees on the x axis?

The answer key says that sin is at a maximum when x=pi/2
So pi/2 = 6x-30(0.04)
 
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What does multiplying a function by a constant do? Does it change how it behaves?
Also note that you get vertical compression from the constant 0.35.

Any sine function reaches its maximum when its argument equals π/2 (You can prove this by differentiating y=A*sin(t)), regardless of any phase shifts brought on by how the argument behaves, and regardless of any compression/stretching brought on by multiplying it by a constant.

I'm glad you interpreted what the answer key says right. sin(t) is at a maximum when t=π/2, not when x equals π/2, but when the entire argument does.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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