When landing after a spectacular somersault

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SUMMARY

The discussion centers on calculating the force exerted by a 50.0 kg gymnast landing after a somersault, with a deceleration of 8.00 times the acceleration due to gravity (g = 9.81 m/s²). The required force can be determined using Newton's second law, F = ma, where 'm' is the mass and 'a' is the deceleration. The total force exerted by the gymnast on the mat is the sum of the force due to her weight and the force required for deceleration, resulting in a total force of 882.9 N.

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  • Understanding of Newton's second law of motion
  • Basic knowledge of forces and acceleration
  • Familiarity with gravitational acceleration (9.81 m/s²)
  • Ability to perform calculations involving mass and force
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Homework Statement



When landing after a spectacular somersault, a 50.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the force she must exert if her deceleration is 8.00 times the acceleration of gravity.


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The Attempt at a Solution

 
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