When p(A)=0 iff p(B)=0 for any polynomial,why same minimal polynomial?

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SUMMARY

For two matrices A and B, the condition p(A)=0 iff p(B)=0 for any polynomial implies that A and B share the same minimal polynomial. This conclusion arises from the definitions of minimal polynomials, where if m_A(A)=0, then m_A(B)=0, leading to the relationship m_B/m_A being a constant. Since both minimal polynomials are monic, this constant must equal 1, confirming that m_A equals m_B. Thus, A and B must have identical minimal polynomials.

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td21
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For two matrices A and B, when p(A)=0 iff p(B)=0 for any polynomial, what will happen? i read that A and B have the same minimal polynomial, why?
 
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td21 said:
For two matrices A and B, when p(A)=0 iff p(B)=0 for any polynomial, what will happen? i read that A and B have the same minimal polynomial, why?

Let [tex]m_A, m_B[/tex] be the minimal polynimials of A and B. Then [tex]m_A (A) = 0\Rightarrow m_A (B) = 0 \Rightarrow m_B / m_A^{(1)}[/tex]
and
[tex]m_B (B) = 0\Rightarrow m_B (B) = 0 \Rightarrow m_A / m_B ^{(2)}[/tex]
[tex]\overset {(1), (2)}{\Rightarrow} m_A = k \cdot m_B[/tex]
with k a constant.
But [tex]m_A, m_B[/tex] are both monic polynomials so, [tex]k=1[/tex]
and finally [tex]m_A = m_B.[/tex]
 
Pretty much the same thing but in slightly differentwords:

Suppose PA(x), of degree n, is the minimal polynomial for A. Then PA(A)= 0 so PA(B)= 0. If This is not the minimal polynomial for B, there exist a polynomial PB, of degree m< n, such that PB(A)= 0. But then PB(A)= 0 contradicting the fact that the mininal polynomial of A has degree n> m.
 

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