When Should You Launch Your Rocket to Mars?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the optimal launch time for a rocket to Mars, considering the alignment of Earth and Mars along a straight line from the sun. The problem involves understanding the orbital mechanics of both planets, specifically under the assumption of circular orbits.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the nature of planetary motion, questioning whether it is uniform or involves acceleration. There are discussions about relating angular positions and velocities of Earth and Mars, with some participants attempting to connect the angle of separation to time taken for alignment.

Discussion Status

There is an ongoing exploration of different approaches to the problem, with participants sharing their thoughts and attempts. Some guidance has been provided regarding the relationship between angular velocities and the concept of relative motion, though no consensus has been reached on a specific method.

Contextual Notes

Participants note that the problem requires understanding the relative speeds of the planets and their angular positions, with some expressing confusion over the constraints and specifics of the problem statement.

Newtime
Messages
347
Reaction score
0

Homework Statement



You are working on a project with NASA to launch a rocket to Mars, with the rocket blasting off from Earth when Earth and Mars are just aligned along a straight line from the sun. As a first step in doing the calculation, assume circular orbits for both planets. If Mars is now 64.7 degrees ahead of the Earth in its orbit around the sun, when should you launch the rocket?

Give your answer in days to the nearest whole number (i.e. 45.6 = 46)

Note: For this problem you need to know the fact that all the planets orbit the sun in the same direction, and the year on Mars is 1.88 Earth years.



Homework Equations



The rotational kinematics equations, but I can't seem to figure out which one to use. If you don't have them handy, here's a link:
http://bama.ua.edu/~jharrell/PH105-S03/exercises/rot_mot_eqs.htm
Sorry, I don't know how to retype those on here.

The Attempt at a Solution



I honestly don't know where to start. I had a few ideas but none of them came close. The answer is 140 days. Any help is appreciated.
 
Last edited by a moderator:
Physics news on Phys.org
What have you tried? How would you describe the motion of the planets? Accelerated, non-accelerated, uniform, non-uniform?

Hint: Angle corresponds to distance.
 
Doc Al said:
What have you tried? How would you describe the motion of the planets? Accelerated, non-accelerated, uniform, non-uniform?

Hint: Angle corresponds to distance.

I didn't write anything down; I just thought out some concepts and what I was doing in my head. The motion is uniform with no radial accelaration but with centripetal accelaration, although I don't think centripetal accelaration comes into play here. My guess would be that the angle has something to do with the time it takes to complete one orbit, I guess I'm having troubel relating the orbit's of Earth and Mars in roder to get one answer.
 
I've tried a few more things since my last post, still nothing, does anyone have any other suggestions?
 
Newtime said:
I didn't write anything down; I just thought out some concepts and what I was doing in my head.
Unless you show us what you're trying, we can't tell if you're on the right track.
The motion is uniform with no radial accelaration but with centripetal accelaration, although I don't think centripetal accelaration comes into play here.
Both planets move uniformly in a circle at different speeds (find those angular speeds). They are centripetally/radially accelerated, but you're right--that doesn't matter here. All you care about is their tangential motion around the circle.

If you had two cars, A and B, with B ahead of A by 100m but A moving faster. Could you figure out how long it takes A to catch up with B? It's the same problem, only with angle instead of distance.
 
Doc Al said:
Unless you show us what you're trying, we can't tell if you're on the right track.

Both planets move uniformly in a circle at different speeds (find those angular speeds). They are centripetally/radially accelerated, but you're right--that doesn't matter here. All you care about is their tangential motion around the circle.

If you had two cars, A and B, with B ahead of A by 100m but A moving faster. Could you figure out how long it takes A to catch up with B? It's the same problem, only with angle instead of distance.

I had tried to regard Mars' orbit as a constant 1 (since I don't know actual speeds, only relative ones), that way Earth's would be 1.88^-1 which was .56 or something like that, I don't have my calculator with me at the moment. And I divided 64.7 by that number and got 121 plus a few decimal places. My logic was that if I regard Mars' orbit as constant, and Earth's orbit as changing, ignoring the fact that they are both orbiting a larger body, I can just use that number and the amount of space (degrees) Earth needs to cath up. Other slight variations of that technique didn't work either.

Also, about the car analogy: I've actually had several problems just like that before except we were given the speeds or accelarations of the cars and coudl relatively easily solve the problem using two or so f the kinematics equations. Here, all I'm supposed to use is the number 1.88 and 64.7, which is what made me think I had to toy with relative velocities.

I've also tried plugging in the actual answer to see where it came from, like a sort of reverse solution, but I couldn't get it either.

Does any of that sound remotely correct?
 
Newtime said:
Also, about the car analogy: I've actually had several problems just like that before except we were given the speeds or accelarations of the cars and coudl relatively easily solve the problem using two or so f the kinematics equations. Here, all I'm supposed to use is the number 1.88 and 64.7, which is what made me think I had to toy with relative velocities.
Ah, but you do have the speeds of the planets.

The speed of Earth = 1 orbit/earth year = 360 degrees/365 days

What's the speed of Mars? (Use the given information to figure it out.)
 
The rocket can be launched anytime you please. There are some constraints missing.
 
Phrak said:
The rocket can be launched anytime you please. There are some constraints missing.
The launch time (with respect to "now") is specified:
Newtime said:
You are working on a project with NASA to launch a rocket to Mars, with the rocket blasting off from Earth when Earth and Mars are just aligned along a straight line from the sun.
 
  • #10
Doc Al said:
The launch time (with respect to "now") is specified:

Then I shall have to learn to read question not as they are written, but as they are intended to mean.
 
  • #11
Hey thanks for all the help guys, I ended up getting caught up with some other work and hadn't had a chance to look at this problem again until last night, but as I'm sure some of you know, all it takes is some time off (of a specific problem) to make you realize how simple it really was. I honestly want to slap myself. (joking, but not really). I sat down, and in about a minute got the right answer and thought, "why did I think that was so hard?"

To anyone who's also trying to get this problem: read the thread, then find the angular velocities in rad/sec for both planets. Angular accelaration=0 and then you establish an arbitrary point (probably Earth's initial position) for position=0 and use whatever angle Mars is ahead of Earth as it's initial position. Use these values for the angular kinematics equation relating final position to initial position, initial velocity times time, and half of the accelaration times the time squared. Since you want both final positions to be the same (planets should be aligned as said in the problem) set the two equations equal to each other. You now should have an equation with just one unknown: final position. Solve for this, then do some unit conversions and you have your answer.

Thanks again for everyone's help in this thread.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
2
Views
2K
Replies
6
Views
5K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
10K
  • · Replies 9 ·
Replies
9
Views
7K