When Will Two Objects With Different Speeds and Accelerations Meet?

[sese]

Homework Statement

Two objects start from same point whit 4s one after another traveling same direction whit
speed₀₁ =5 m/s ; a₀₁=0.5 m/s²
and
speed₀₂=2 m/s ; a ₀₂=1 m/2²

$$\tau$$=4s

Find at what time the objects meet?

Answer:28 s

Homework Equations

d₀₁=S₀₁*t₀₁*(a₀₁+t₀₁²)/2
d₀₂=S₀₂*t₀₂*(a₀₂+t₀₂²)/2
(I think!)

The Attempt at a Solution

t₀₁=S₀₁/a₀₁
t₀₂=S₀₂/a₀₂

After fiding the distance from equation's i get stuck

 

[tiny-tim]

Welcome to PF!

Hi sese! Welcome to PF!

(btw, we usually use v or u for speed, not s, and s for distance, not d )

Homework Equations

d₀₁=S₀₁*t₀₁*(a₀₁+t₀₁²)/2
d₀₂=S₀₂*t₀₂*(a₀₂+t₀₂²)/2

No, those equations are wrong.

You need s = v_it + at²/2.

See the PF Library on constant acceleration