Where will two objects of different masses meet in space?

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Homework Help Overview

The problem involves two objects of different masses, 3 kg and 7 kg, positioned 10 meters apart in space, which are released to move towards each other due to gravitational attraction. The objective is to determine the location where the lighter object will meet the heavier object.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for multiple equations to solve for the distances r1 and r2, questioning how to relate these variables effectively. There is also mention of using the center of mass equation to find the meeting point.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the necessary equations. Some guidance has been offered regarding the center of mass, but there is no consensus on the approach to take due to the complexity of the variables involved.

Contextual Notes

Participants note the challenge of having three variables (r, r1, r2) with insufficient equations to solve the problem, indicating a need for further clarification or assumptions regarding the setup.

Dumbledore211
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Homework Statement



Two objects of mass m=3kg and M=7kg are held at a distance of 10 meter in space and then released. They move towards each other due to mutual gravitation attraction. Determine the location of their meeting of the object mass m

Homework Equations



r= mr1+ Mr2/m+M

The Attempt at a Solution


The objects will meet at their center of their mass. What I am finding difficult to understand is the method of finding out r1 and r2 with respect to m from the given information
 
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You have two variables r1 and r2 ... so you need two equations.
The other one is r=r1+r2
 
We really don't know the value of r which means there are actually three variables. I have tried to solve it by using your method but 2 equations won't suffice in this case. We need one more equation
 
Dumbledore211 said:
We really don't know the value of r which means there are actually three variables. I have tried to solve it by using your method but 2 equations won't suffice in this case. We need one more equation

You can find the center of mass using the equation:

x_c=\frac{\sum{mx}}{\sum{m}}

Take as x = 0 as the initial location of mass m.
 
You mean I should take r1=0 @Chestermiller
 
Dumbledore211 said:
You mean I should take r1=0 @Chestermiller
Yeah, although it doesn't really matter. Take the origin anywhere you want. The answer will come out the same (in terms of the distances from each of the two masses).
 

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