Where Are the First Five Intensity Maxima for Copper in a Powder Diffractogram?

[Lindsayyyy]

Hi everyone

Homework Statement

I want to make a powder diffractogram of copper. Where do I expect the first five intensity maximums when the used wavelength is lambda=0,711 *10^-10 m

Homework Equations

Bragg equation
2d sin(omega)=m*lambda

The Attempt at a Solution

I think coppers structure is fcc but I have a problem finding my distance between the lattice planes because I don't know on which planes the scattering will take place.

Thanks for your help

 

[member 553083]

!The first five intensity maxima for copper can be found using the Bragg equation. The Bragg equation states that 2d sin(omega)=m*lambda, where d is the distance between lattice planes, omega is the angle between the incident and reflected beam, m is the order of reflection, and lambda is the wavelength. Using this equation, you can calculate the angles and distances for the first five maxima. For example, for the first maxima, m=1 and d=0.711*10^-10/2sin(omega). Once you have the distances, you can use them to calculate the angles of incidence and reflection for each maxima.