Where Did I Go Wrong in My Big Bang Nucleosynthesis Calculation?

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SUMMARY

The discussion centers on the calculation of the scale factor during Big Bang Nucleosynthesis (BBN). The correct formula for the scale factor is established as a(t) = (4H_0^2 Ω_{r,0})^{1/4} √t, which applies in a flat radiation-dominated universe. The user initially derived a(t) = (3tH_0 √Ω_{r,0})^{1/3} but overlooked the relationship H = (1/a)(da/dt) during integration. This oversight was identified and corrected, confirming the straightforward nature of the problem.

PREREQUISITES
  • Understanding of Big Bang Nucleosynthesis (BBN)
  • Familiarity with the Friedmann equation
  • Knowledge of scale factors in cosmology
  • Basic calculus for integration
NEXT STEPS
  • Study the Friedmann equations in detail
  • Learn about the implications of a radiation-dominated universe
  • Explore the derivation of scale factors in cosmology
  • Investigate the role of Hubble's constant (H_0) in cosmological models
USEFUL FOR

Students and researchers in astrophysics, particularly those focusing on cosmology and the early universe, will benefit from this discussion.

Niles
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[SOLVED] Astrophysics homework: Cosmology

Homework Statement


I have to show that during the Big Bang Nuchleosynthesis, the scalefactor is approximately given by

a(t) = \left( {4H_0^2 \Omega _{r,0} } \right)^{1/4} \sqrt t

The Attempt at a Solution


Ok, since the BBNS is during the first ~3 minutes after Big Bang, we are in a flat radiation-dominated Universe. The Friedmann equation takes the form:

\frac{{H^2 }}{{H_0^2 }} = \frac{{\Omega _{r,0} }}{{a^4 }}

I rewrite and integrate this and I get that

a(t) = \left( {3tH_0 \sqrt {\Omega _{r,0} } } \right)^{1/3}

Can you guys find my error? This problem seems quite straight-forward, but I can't find my error.
 
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I think you forgot this:

H = \frac{{1}}{{a}} \frac{{da}}{{dt}}

or else you lost track of another one of the a's during your integration.
 
That's right, I forgot that. I worked it out now - it really is straight-forward.

Thanks.
 

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