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J.live
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Basic Circuit - Nodal Analysis
I am trying to find ix and iy.
Here is the figure
http://tinypic.com/view.php?pic=x2mr93&s=7
Node 1
-3 + V1/0.2 + (V1-V2/0.5) = 0
-.06 + 0.1V1 +0.2V1 - 0.2V2 =0
-.06 + 0.3V1 -0.2V2 = 0
Node 2
-6 +( V2 - V1/0.1) + V2/0.5=0
-0.3 + 0.5V2 - 0.5V2 + V2/0.5=0
0.6V2 = 0.5V1 +0.3
V2= 0.5V1 + 0.3 / 0.6
Substituting V2 in V1
0.3V1 - 0.2( (0.5V1 + 0.3 )/ 0.6)=0
.14 V1 =.159
V1 = 1.13
Substituting V1 back in V2
V2 = 0.5(1.13 + 0.3)/ 0.6 = 1.19 V
ix = 1.19-1.13 / .2 = .3 ?
iy = V2 / R = 1.19/1 = 1.19 ?
P.S The answers are iy = -1.5 ix = 1.5.
Where exactly am I going wrong with this? I don't think I missed any variables , etc.Is there a conceptual mistake ?Please help me out here. Thanks.
Homework Statement
I am trying to find ix and iy.
Here is the figure
http://tinypic.com/view.php?pic=x2mr93&s=7
The Attempt at a Solution
Node 1
-3 + V1/0.2 + (V1-V2/0.5) = 0
-.06 + 0.1V1 +0.2V1 - 0.2V2 =0
-.06 + 0.3V1 -0.2V2 = 0
Node 2
-6 +( V2 - V1/0.1) + V2/0.5=0
-0.3 + 0.5V2 - 0.5V2 + V2/0.5=0
0.6V2 = 0.5V1 +0.3
V2= 0.5V1 + 0.3 / 0.6
Substituting V2 in V1
0.3V1 - 0.2( (0.5V1 + 0.3 )/ 0.6)=0
.14 V1 =.159
V1 = 1.13
Substituting V1 back in V2
V2 = 0.5(1.13 + 0.3)/ 0.6 = 1.19 V
ix = 1.19-1.13 / .2 = .3 ?
iy = V2 / R = 1.19/1 = 1.19 ?
P.S The answers are iy = -1.5 ix = 1.5.
Where exactly am I going wrong with this? I don't think I missed any variables , etc.Is there a conceptual mistake ?Please help me out here. Thanks.
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