Where Did I Go Wrong in Solving the Inequality?

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The discussion revolves around solving the inequality 1/x < 4, particularly for negative and positive values of x. For x > 0, the solution indicates x must be greater than 1/4, while for x < 0, the calculations suggest x must be less than -1/4, but the original inequality holds for all x in the interval [-1/4, 0). Participants emphasize the importance of recognizing the fixed condition that x is negative, which can lead to confusion when interpreting results. The conversation highlights the need to carefully consider the implications of multiplying by negative values and the reversibility of inequalities. Ultimately, understanding the constraints of the problem is crucial for accurate solutions.
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Homework Statement
Solve ##\dfrac{1}{x}<4##
Relevant Equations
Inequalities
##\dfrac{1}{x}<4##

For ##x>0##:

##1<4x \Rightarrow x>\dfrac{1}{4}##

For ##x<0##:

##1<4x \Rightarrow \dfrac{1}{4}<x \Rightarrow x<-\dfrac{1}{4}##

But the problem is ##x<0## works in the original expression instead of just ##x<-\dfrac{1}{4}##, so from calculations alone I missed ##[-\dfrac{1}{4}, 0)##. I feel conceptually I'm not understanding inequalities or my calculations are wrong.
 
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When you multiply both sides by a negative valued x, the inequality flips direction.

##4x<1##.

You also didn't handle what comes after that very well in your attempt- if you did believe ##1/4<x## then there would be no solutions since x has to be negative. Think through carefully what the next step needs to be here.

Sometimes it helps to say if we're assuming x is negative, replace it with -y and assume y is positive.
 
I'm getting confused from assuming ##x<0##, because doing the calculation results in ##x<\dfrac{1}{4}##, which by itself means ##x## is positive in ##[0,\dfrac{1}{4})##. But I think I'm starting to understand I must keep in mind the starting assumption ##x## is negative, so ##x<0## is a fixed condition, despite the calculation ending up showing ##x<\dfrac{1}{4}##.
 
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RChristenk said:
I'm getting confused from assuming ##x<0##, because doing the calculation results in ##x<\dfrac{1}{4}##, which by itself means ##x## is positive in ##[0,\dfrac{1}{4})##. But I think I'm starting to understand I must keep in mind the starting assumption ##x## is negative, so ##x<0## is a fixed condition, despite the calculation ending up showing ##x<\dfrac{1}{4}##.
If we choose any ##x## in ##(-\infty,0)##, it is true that ##x## is in ##(-\infty,1/4)##. The latter condition does not contradict the first condition. Does this help?
 
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docnet said:
If we choose any ##x## in ##(-\infty,0)##, it is true that ##x## is in ##(\infty,1/4)##. The latter condition does not contradict the first condition. Does this help?
Yes I understand better now. Thank you.
 
RChristenk said:
Yes I understand better now. Thank you.
The second interval should be ##(-\infty,1/4)##, not ##(\infty,1/4)##! Sorry about the typo, I'm very tired and it somehow got past me.
 
RChristenk said:
I'm getting confused from assuming ##x<0##, because doing the calculation results in ##x<\dfrac{1}{4}##, which by itself means ##x## is positive in ##[0,\dfrac{1}{4})##. But I think I'm starting to understand I must keep in mind the starting assumption ##x## is negative, so ##x<0## is a fixed condition, despite the calculation ending up showing ##x<\dfrac{1}{4}##.
That's good. The equation tells you that AT LEAST ##x\lt \dfrac{1}{4}##. But that was with the additional assumption that ##x \lt 0##. So both must be true. So ##x \lt 0## for this case.
 
Another thing to be careful about with inequalities is reversibility of the inference.
Showing that ##1/x<4## and ##x<0## leads to ##x<1/4## does not of itself prove that ##x<0## and ##x<1/4## implies ##1/x<4##.
 
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