Where Does \(\frac{1}{2}x\) Come From at \(k=1\)?

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SUMMARY

The expression \(\frac{1}{2}x\) arises when evaluating limits as \(k\) approaches 1, specifically due to the indeterminate form \(0/0\) encountered in the denominator \(2(k-1)\). This situation necessitates the application of L'Hôpital's Rule, which simplifies the limit evaluation process. The limit \(\lim_{t\to0}\frac{\sin(t)}{t}\) is also referenced, yielding a result of 1 when applying L'Hôpital's Rule. The discussion emphasizes the importance of recognizing indeterminate forms in calculus.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with L'Hôpital's Rule
  • Knowledge of indeterminate forms
  • Basic trigonometric limits, specifically \(\lim_{t\to0}\frac{\sin(t)}{t}\)
NEXT STEPS
  • Study L'Hôpital's Rule in depth, including its applications and limitations
  • Explore advanced limit techniques beyond L'Hôpital's Rule
  • Review trigonometric limits and their derivations
  • Practice solving problems involving indeterminate forms in calculus
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Students studying calculus, particularly those focusing on limits and indeterminate forms, as well as educators seeking to clarify these concepts in their teaching.

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Homework Statement



half_wave.jpg


How did [itex]\frac{1}{2}x[/itex] come from at k=1?

Homework Equations

The Attempt at a Solution



because k=1 will make the first term at denominator 2(k-1) = [itex]\frac{0}{0}[/itex]
 
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izen said:

Homework Statement



half_wave.jpg


How did [itex]\frac{1}{2}x[/itex] come from at k=1?

Homework Equations



The Attempt at a Solution



because k=1 will make the first term at denominator 2(k-1) = [itex]\frac{0}{0}[/itex]
Yes. The [itex]\ \frac{1}{2}x\[/itex] comes from the fact that the first term has the form 0/0 as k → 1.

What is [itex]\displaystyle \ \lim_{t\to0}\frac{\sin(t)}{t}\ ?[/itex]
 
SammyS said:
Yes. The [itex]\ \frac{1}{2}x\[/itex] comes from the fact that the first term has the form 0/0 as k → 1.

What is [itex]\displaystyle \ \lim_{t\to0}\frac{\sin(t)}{t}\ ?[/itex]

Use L' Hopital's Rule --> [itex]\displaystyle \ \lim_{t\to0}cos(t) = 1[/itex]

thank you SammyS
 

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