Where Does the Electric Potential Equal Zero Along the X-axis?

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SUMMARY

The electric potential along the x-axis equals zero at x = 2.0 m, determined by two charges: +2q at the origin and -3q at x = 5 m. The relevant equation used is V = kq/r, where the potentials from both charges were summed and set to zero. The calculation involved rearranging the equation 2kq(5-x) = 3kqx, leading to the solution after canceling k and q. The solution process is confirmed to be correct without errors.

PREREQUISITES
  • Understanding of electric potential and its scalar nature
  • Familiarity with Coulomb's law and the equation V = kq/r
  • Basic algebra for rearranging equations
  • Knowledge of charge interactions on the x-axis
NEXT STEPS
  • Study the concept of electric field and its relation to electric potential
  • Explore the principle of superposition in electrostatics
  • Learn about the effects of multiple charges on electric potential
  • Investigate graphical methods for visualizing electric potential distributions
USEFUL FOR

Students in physics, particularly those studying electrostatics, as well as educators and anyone interested in understanding electric potential calculations in systems with multiple charges.

cuppy
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Two charges lie on the x-axis +2q at the origin and -3q at x=5m. The point on the x-axis where the electric potential has a zero value is??

relevant equations-
V=kq/r

my solution-
since electric potential is a scalar quantity i reasoned that when you add the potentials of both charges and equate that to zero i should be able to find where electric potential is zero. i drew out a diagram and my working out is -

V= k(2q)/x + k(-3q)/5-x = 0

rearranging 2kq(5-x)=3kqx

the k and q cancel giving 10-2x=5 ===> solving gives x=2.0m.

have i made any errors in my working or is it all good? thanks in advance :-p
 
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Yep - looks good.
 

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