- #1
Joseph Nechleba
- 4
- 0
I have a question regarding electric potential and infinity. So,
"A square of side length a with uniformly distributed positive charge lies on the yz plane with its center at the origin. What does the graph of the potential along the x-axis look like?
The answer given in the textbook is a bell-curved-shaped graph with its maximum at x=0. My question is, Why is there a maximum? According to the equation for potential of a point charge, v = k|Q|/(x), shouldn't the potential approach positive infinity as x approaches zero from either direction, as electric potential is a scalar and the charge is uniform?
I am hoping someone can clear my conceptual misunderstanding.
"A square of side length a with uniformly distributed positive charge lies on the yz plane with its center at the origin. What does the graph of the potential along the x-axis look like?
The answer given in the textbook is a bell-curved-shaped graph with its maximum at x=0. My question is, Why is there a maximum? According to the equation for potential of a point charge, v = k|Q|/(x), shouldn't the potential approach positive infinity as x approaches zero from either direction, as electric potential is a scalar and the charge is uniform?
I am hoping someone can clear my conceptual misunderstanding.