Where does the equation C=2*sqrt(km) for Critical Damping come from?

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Homework Help Overview

The discussion revolves around the equation C=2*sqrt(km) related to critical damping in the context of a ruler cantilever experiment. Participants are exploring the meaning of critical damping and its implications for the behavior of a damped spring system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand the derivation and significance of the critical damping equation. Questions about the physical interpretation of critical damping in relation to a ruler cantilever are raised, along with discussions on solving the associated differential equations.

Discussion Status

The discussion is active, with participants sharing insights and references to external resources. Some have provided mathematical approaches to the problem, while others are seeking clarification on the concepts involved. There is no explicit consensus yet, but various interpretations and methods are being explored.

Contextual Notes

Some participants mention the need for background information and suggest that introductory physics textbooks may contain relevant discussions and derivations of the critical damping formula.

physics51
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Homework Statement
what's the background on this equation, I can't find anything about I, what can you guys tell me about it related to damping, when to use it, how to derive it, what it means, etc.? Anything is useful!! Thank you!!
Relevant Equations
C= 2 sqrt km
Im using this equation to find the damping from a ruler cantilever experiment. Any information about what critical damping really means and how it reflects in a ruler cantilever is also really helpful. Thank you again.
 
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From the context I guess that you are discussing a damped spring pendulum with the equation of motion
$$m \ddot{x}=-C \dot{x} - k x.$$
To solve this equation a nice trick is to make the substitution
$$x(t)=\exp(\lambda t) y(t).$$
Plug this into the equation and check that then ##y## fulfills
$$m \ddot{y}+(C+2 \lambda m) \dot{y} + [k+\lambda(C+\lambda m)]y=0.$$
Now make ##\lambda=-C/(2m)## to get rid of the term with ##\dot{y}##. Then the equation of motion for ##y## simplifies to
$$m\ddot{y} + \left (k-\frac{C^2}{4m} \right) y=0.$$
Now discuss what happens for the different values of the expression in the bracket,
$$k-\frac{C^2}{4m}<0, \quad k-\frac{C^2}{4m}=0, \quad k-\frac{C^2}{4m}>0.$$
 
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For an ODE with constant coefficients I’d just make the ansatz ##x(t) = A \exp(\lambda t)## and solve the characteristic equation, but any way that works works.
 
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Well, then you've the trouble with exactly the case of critical damping ;-).
 
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physics51 said:
what's the background on this equation, I can't find anything about I,
Where did you look? Most college-level introductory physics textbooks will have a discussion of critical damping and will derive this formula.
 

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