Where does this inequality come from?

  • Context: Graduate 
  • Thread starter Thread starter michaelxavier
  • Start date Start date
  • Tags Tags
    Inequality
Click For Summary
SUMMARY

The discussion centers on the inequality derived from the identity in Rudin's "Principles of Mathematical Analysis," 3rd edition, specifically on page 10. The identity states that b^n - a^n = (b - a)(b^(n-1)*a^0 + b^(n-2)*a^1 + ... + b^1*a^(n-2) + b^0*a^(n-1)). The inequality b^n - a^n < (b - a)n*b^(n-1) holds true under the condition 0 < a < b. Participants clarify that the condition implies b^(n-2)a < b^(n-1), reinforcing the validity of the inequality.

PREREQUISITES
  • Understanding of polynomial identities and their derivations
  • Familiarity with inequalities in mathematical analysis
  • Knowledge of the properties of exponents
  • Basic comprehension of limits and continuity in calculus
NEXT STEPS
  • Study the derivation of polynomial identities in mathematical analysis
  • Explore the application of inequalities in calculus
  • Learn about the implications of the Mean Value Theorem
  • Investigate the role of limits in establishing inequalities
USEFUL FOR

Mathematics students, educators, and anyone studying real analysis who seeks to deepen their understanding of polynomial inequalities and their applications.

michaelxavier
Messages
14
Reaction score
0
In Rudin's Principles of Mathematical Analysis, 3rd ed., I encountered the following on p. 10, and I'm not really sure where it comes from. I'll write it just as it is shown in the book.

The identity
b^n-a^n=(b-a)(b^(n-1)*a^0 + b^(n-2)*a^1 + ... + b^1*a^(n-2) + b^0*a^(n-1))
yields the inequality
b^n-a^n<(b-a)n*b^(n-1)
when 0<a<b

I understand where the indentity comes from. I'm just confused about the inequality, and I was curious. Thanks for sharing any ideas.
 
Physics news on Phys.org
0<a<b implies, for instance, that b^(n-2)a < b^(n-1). Do you see it now?
 
Oh, of course. Thanks so much!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
7K