Where is the Function f(z) = (z+1)/(z-i) Differentiable on the Complex Plane?

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SUMMARY

The function f(z) = (z+1)/(z-i) is differentiable on the complex plane except at the point z = i, where the denominator becomes zero. To determine differentiability, the Cauchy-Riemann (CR) equations are applied, which require the function to be expressed in terms of its real and imaginary components. The derivative f' can be calculated using the quotient rule, similar to real-valued functions, after simplifying the expression by multiplying by the complex conjugate of the denominator.

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Homework Statement



Find where;

f(z) = (z+1)/(z-i)

is differentiable on the complex plane and find the formulas for f'

Homework Equations



CR equations;

if f(z) = u(x,y) + iv(x,y)

u_x - v_y = 0
v_x + u_y = 0

if function is differentiable


The Attempt at a Solution



My problem is splitting this into its real and imaginary components. Once I have it in re, I am parts I know how to use the CR equations to find whether it's differentiable and then find the derivative.
 
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To simplify the problem slightly write your fraction as:

[tex] \frac{z+1}{z-i}=\frac{(z-i)+i+1}{z-i}=1+\frac{1+i}{z-i}[/tex]

Now use the definition of z that is [itex]z=x+iy[/itex]. Then multiply top and bottom by the complex conjugate of the denominator.
 
Last edited:
If the problem were
[tex]\frac{x+1}{x-1}[/tex]
with x a real number you could differentiate it using the quotient rule couldn't you?

Well, the rules for differentiating a function of complex numbers are just the same as for functions of real numbers! Differentiate the above and then replace x by z.
 

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