Where is the voltage potential zero given two points?

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SUMMARY

The discussion focuses on determining the locations where the electric potential is zero between two fixed charges: a positive charge with a magnitude ten times that of a negative charge. The relevant equation used is V = kq/r, where k is the Coulomb's constant. The participants confirm that the solution will yield a quadratic equation, indicating two distinct points where the potential equals zero. The equation is refined to 0 = k10q/(d-x) + k(-q)/x, which is essential for finding the correct distances relative to the negative charge.

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xcmntgeek
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Homework Statement


Two charges are fixed in place with a separation d. One charge is positive and has ten times (n = 10) the magnitude of the other charge, which is negative. The positive charge lies to the left of the negative charge, as in Figure 19.10. Relative to the negative charge, locate the two spots on the line through the charges where the total potential is zero relative to d.
Positive distance to the left of -q: ____ X d
Positive distance to the right of -q: _____ X d


Homework Equations



V= kq/r

The Attempt at a Solution



0= k10q/(d-xd)+k-q/xd

That's about all I know, I'm sure we'll end up with a quadratic because there will be two spots where the potential = 0.
 
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xcmntgeek said:

The Attempt at a Solution



0= k10q/(d-xd)+k-q/xd

Shouldn't this equation be


\frac{k 10q}{d-x} + \frac{-qk}{x}=0


I didn't really draw out the problem as I haven't done these questions in a few years.
 

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