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## Homework Statement

A point charge q = -0.5nC is fixed at the origin. Where must a proton be placed in order for the electrical force acting on it to be exactly opposite its weight?

## Homework Equations

F=

k(q1)(q2)

------------

r^2

## The Attempt at a Solution

Trying to solve for distance (r), but coming across a few problems;

If the force acting on it is exactly opposite its weight, does this make F=0?

should I be substituting 0 for F?

Where would I substitute -0.5? in q1 or q2?

And what would I place in the other?

???