Which anion could be used to selectively remove silver ions?

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SUMMARY

The discussion focuses on identifying an anion that can selectively remove silver ions (Ag+) from solution, with options including chloride (Cl), sulfate (SO4), and carbonate (CO3). Each of these anions forms precipitates with silver, but the effectiveness of selective precipitation depends on the solubility rules and the presence of other cations in the solution. It is crucial to determine which anion results in the lowest molar concentration of Ag+ in the saturated solution to achieve selective precipitation without affecting other ions.

PREREQUISITES
  • Understanding of solubility rules in chemistry
  • Knowledge of precipitation reactions
  • Familiarity with transition metal chemistry
  • Basic concepts of ionic compounds and their interactions
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  • Research the solubility of silver salts with chloride, sulfate, and carbonate anions
  • Study the principles of selective precipitation in analytical chemistry
  • Explore the role of cations in precipitation reactions
  • Investigate the properties of soluble and insoluble anions
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Chemistry students, analytical chemists, and professionals involved in water treatment or metal recovery processes will benefit from this discussion.

HHH
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The question is, which anion could be used to selectively remove silver ions from solution? The options are Cl, SO4, or CO3.

All 3 of them form precipitates, but is there any that is better than the others?
 
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Do you know what other cations are present in the solution? If you're trying to selectively precipitate silver ions, it is important that the salt you add does not also precipitate other ions.
 
Another thing to consider: for which of the three potential precipitates molar concentration of Ag+ in the saturated solution is the lowest?
 
Check your solubility rules and that should guide you. Transition metals are generally insoluble unless paired with another anion which is soluble.
 
brake4country said:
Transition metals are generally insoluble unless paired with another anion which is soluble.

And what are "soluble" anions?
 

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