Which bulb will get fused first?

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SUMMARY

When two bulbs rated at 25 watts and 100 watts are connected in series to a 440-volt supply, the bulb that will fuse first is determined by calculating their resistances. The formula P=I²R is used to analyze the current through each bulb. The bulb with the lower power rating, in this case, the 25-watt bulb, will fuse first due to exceeding its power rating when subjected to the total voltage.

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Homework Statement



If two bulbs of power 25 watt and 100 watt each rated at 220 volts are connected in series with a supply of 440 volts. Which bulb will be fused?

The Attempt at a Solution



This is what I think I have to do-
Find out the resistances of each bulb from the data given.
Use P=I2R for each bulb and find out if it is greater than its power rating. The one with higher power rating will get fused.

Is this right?
 
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Hi Abdul! :wink:
Abdul Quadeer said:
This is what I think I have to do-
Find out the resistances of each bulb from the data given.
Use P=I2R for each bulb and find out if it is greater than its power rating. The one with higher power rating will get fused.

That's right! :smile:

(I assume you're finding I from the total resistance)
 

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