Which Compound Could Be X?

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SUMMARY

The discussion centers on determining the identity of compound X based on combustion analysis. When 1.11 g of compound X is burned, it produces 1.98 g of carbon dioxide and 0.81 g of water, leading to the conclusion that compound X is likely to be CH3CH2COOH (acetic acid). The calculation involves determining the moles of carbon and hydrogen from the combustion products and ensuring the total mass aligns with the initial mass of compound X. The balanced combustion equation is crucial for this analysis.

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Chemistry students, educators, and professionals involved in organic chemistry and combustion analysis will benefit from this discussion.

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Homework Statement


When 1.11 g of a compound X is completely burnt,1.98 g of carbon dioxide and 0.81 g of water were formed. Which of the following could be X?

A. CH_{3}CH_{2}CH_{3}
B. CH_{3}CH_{2}COOH
C.CH_{3}COCH_{3}
D.C_{6}H_{5}CH_{2}OH

The Attempt at a Solution



I tried

C_{x}H_{y} + {x+\frac{y}{4}}O_{2} \rightarrow
XC0_{2} + \frac{y}{2}H_{2}O

but how about the oxygen atom(s) within compound X?

How can I form a balanced equation for X containing O?

Sorry about the equations and formulae... can't get the subscripts in the right positions.
 
Last edited:
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The only things in the product that you can be absolutely sure come from the reactant is the carbon and hydrogen. So, from the water and CO2, calculate how many moles of C and H you had to begin with. What's the mass of this amount of carbon and hydrogen - is it enough to account for all of the 1.11 g you had to begin with?
 
Got it. Useful hint.Thanks. Answer's B. :smile:
 

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