Which Copper Oxide Was Used in the Experiment?

  • Thread starter Thread starter Bashyboy
  • Start date Start date
  • Tags Tags
    Copper
Click For Summary
SUMMARY

The experiment involved heating 1.51 g of a copper oxide (either CuO or Cu2O) in a crucible under anoxic conditions, resulting in the production of 1.21 g of pure copper. The key to determining which oxide was used lies in calculating the mass ratios of copper to the total mass of the compound. For CuO, the mass ratio is approximately 0.67, while for Cu2O, it is approximately 0.80. Given the experimental results, the oxide used in the experiment was CuO, as the calculated ratio aligns more closely with the observed data.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Familiarity with the concepts of atomic weight and molar mass
  • Basic knowledge of copper oxides, specifically CuO and Cu2O
  • Experience with mass ratio calculations in chemistry
NEXT STEPS
  • Study the principles of stoichiometry in chemical reactions
  • Learn about the properties and reactions of copper oxides
  • Explore the concept of mass ratios in chemical compounds
  • Investigate methods for conducting experiments in anoxic environments
USEFUL FOR

Chemistry students, educators, and anyone interested in understanding the properties and reactions of copper oxides in laboratory settings.

Bashyboy
Messages
1,419
Reaction score
5

Homework Statement


Oxides of copper include CuO and Cu2O. In a crucible, you heat 1.51 g of one of these copper oxides in the absence of air and obtain 1.21 g of pure Cu. Which oxide did you have?


Homework Equations





The Attempt at a Solution


I am really quite uncertain regarding how to even begin a problem like this.
 
Physics news on Phys.org
Bashyboy said:

Homework Statement


Oxides of copper include CuO and Cu2O. In a crucible, you heat 1.51 g of one of these copper oxides in the absence of air and obtain 1.21 g of pure Cu. Which oxide did you have?

Homework Equations


The Attempt at a Solution


I am really quite uncertain regarding how to even begin a problem like this.

Chemistry has been a while for me, but I think you do this using simple ratios. Looking up the "standard atomic weight" of Oxygen, you get approximately 16 (rounding up). For copper, it's approx. 64 (again, rounding up). Let's say you broke up a single bond in the compound CuO, giving you one copper atom and one oxygen atom. The fraction of the total mass made up by copper would then be

(atomic weight of Cu)/(atomic weight of Cu + atomic weight of O)

The trick is that this is also the fraction of the total mass of the whole sample that you would expect to be in copper (since you'd get one copper atom for every oxygen atom). In contrast, for Cu2O, you'd get 2 copper atoms for every one oxygen atom, and the fraction of the total mass made up by copper would then be
(2*atomic weight of Cu)/(2*atomic weight of Cu + atomic weight of O)

So, assuming that heating the sample in a vacuum simply breaks the chemical bonds and gives you back the individual elements (which is the part I'm unsure about because I'm no chemist), then whichever one of these equations best matches the measured ratio of copper mass to total compound mass (1.21/1.51) tells you which compound you started with.
 
cepheid said:
Let's say you broke up a single bond in the compound CuO, giving you one copper atom and one oxygen atom.

It is not a single bond actually - there are two bonds between copper and oxygen in CuO. But apart from that your idea about mass ratios is perfectly valid,
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
10K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 10 ·
Replies
10
Views
18K
Replies
16
Views
22K
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 2 ·
Replies
2
Views
10K