Which of the Following is a solution to the differential Equation

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SUMMARY

The differential equation in question is t²y" - 2ty' + 2y = 0. The solutions tested include y = t⁴, y = t, and others. The analysis confirmed that y = t is a valid solution, while y = t⁴ does not satisfy the equation due to an arithmetic error in the calculations. The discussion highlights that differential equations can have multiple solutions, emphasizing the importance of verifying each candidate solution.

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Northbysouth
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Homework Statement


Which fot he following is a solution to the differential equation:

t2y" - 2ty' + 2y = 0

a)e-2tt3

b)et

c)t

d) t4

I have attached an image of the question

Homework Equations





The Attempt at a Solution



I tried answer d first:

y = t4

y' = 4t3

y" = 12t2

Plugging in these derivatives:

t2(12t2) - 2t(4t3) + 2(t4) = 0

I also checked with y = t and this solution works as well. So how do I distinguish between which one is the correct answer?
 

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\neq
Northbysouth said:
t2(12t2) - 2t(4t3) + 2(t4) = 0

I also checked with y = t and this solution works as well. So how do I distinguish between which one is the correct answer?

I think you just made an arithmetic mistake ;)
t^2(12t^2) - 2t(4t^3) + 2(t^4) = 12t^4 - 8t^4 + 2t^4 = 6t^4 \neq 0

In many cases, DE's can have multiple different solutions.
 

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