Who can fill the brace: -3,0,26,252,()

  • Context: High School 
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Discussion Overview

The discussion revolves around identifying a missing number in the sequence -3, 0, 26, 252, (). Participants explore potential patterns and mathematical reasoning related to the sequence, with some suggesting it may be part of an IQ test or pattern recognition challenge.

Discussion Character

  • Exploratory, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant questions the conditions under which the brace could contain any integer, seeking clarification on the problem's constraints.
  • Another suggests that the sequence might be part of a pattern-filling exercise, implying it could be arbitrary.
  • Multiple participants present a mathematical expression related to the sequence, yielding a specific numerical result, but the relevance to the original question is unclear.
  • A participant proposes changing the first number in the sequence from -3 to -6, prompting further exploration of how this alteration affects the sequence.
  • Another participant analyzes the implications of using -6, suggesting that it leads to an ambiguous sequence with multiple interpretations based on different mathematical frameworks, such as Fibonacci or quadratic sequences.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the sequence and the implications of changing its initial value. There is no consensus on the correct approach or the next number in the sequence.

Contextual Notes

The discussion includes various interpretations of the sequence and its mathematical properties, with participants relying on different assumptions and frameworks that remain unresolved.

cc123
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who can fill the brace:
-3,0,26,252,()
thanks a lot!
 
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?? In what way? is there any reason that brace could not contain any integer? What are the conditions you are not telling us about?
 
most probably it's some pointless IQ test where we go on filling in patterns and numbers and all that stuff..
 
Whew. I get
[tex]\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144[/tex]
There's no rounding needed since it's even.
 
CRGreathouse said:
Whew. I get
[tex]\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144[/tex]
There's no rounding needed since it's even.

d00d seriously.. what did u just do??
 
CRGreathouse said:
Whew. I get
[tex]\sigma(4n\cdot2^{2^{2^{3-1}}})-4=2,097,144[/tex]
There's no rounding needed since it's even.

Oh, well, of course!
 
Can you change the first to -6, instead of -3?
 
in any way i think.there are many answers if you can tell the reason.
to Dodo, if u change the first to -6,what is your answer?thank u!
 
With a -6... is it ambiguous. It would be the sequence
[tex]2^2-10, \ \ \ \ \ \ 2^3-8, \ \ \ \ \ \ 2^5-6, \ \ \ \ \ \ 2^8-4[/tex]​
so the next is [tex]2^n-2[/tex], and n depends on how you interpret the sequence of exponents: if it is Fibonacci, then n=11 for a value of 2046, if it is a quadratic, n=12 and you get 4094.
 

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