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Is this a spontaneous symmetry breaking?

why the ground state is not of zero angular momentum?

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- Thread starter wdlang
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- #1

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Is this a spontaneous symmetry breaking?

why the ground state is not of zero angular momentum?

- #2

mfb

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Why do you expect something special to get the same in quantum mechanics? There are orbitals with angular momentum, and if there are is a single electron in one of those orbitals you get a nonzero total angular momentum.

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A classical, charged, rotating ring has no dipole moment, but nonzero angular momentum.

Why do you expect that this is something special to get the same in quantum mechanics? There are orbitals with angular momentum, and if there are is a single electron in one of those orbitals you get a nonzero total angular momentum.

intuitively, a non-rotating state is lower in energy than a rotating one

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mfb

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