Why Are Hadrons Heavier Than Their Quark Components?

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Discussion Overview

The discussion centers on the question of why hadrons, such as protons, are significantly heavier than the sum of their constituent quarks. Participants explore concepts related to binding energy, the role of gluons, and the implications of quark confinement in the context of nuclear and particle physics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant notes that the combined mass of the quarks in a proton is around 12 MeV, while the proton itself is approximately 950 MeV, suggesting a large negative binding energy.
  • Another participant agrees that separating the quarks would require significant energy, indicating a negative binding energy.
  • A participant questions the significance of having a negative binding energy and its implications for the mass of hadrons.
  • Discussion includes the idea that the mass of hadrons arises not only from the quark masses but also from the potential and kinetic energy of the quarks and the presence of dynamical quarks, which contribute additional mass.
  • Participants discuss the repulsive nature of the nucleon-nucleon potential at short distances and whether this is phenomenological or has a fundamental explanation.
  • Some participants suggest that the Pauli exclusion principle plays a role in the repulsion observed at short distances between nucleons.
  • There is mention of various models, including the One Boson Exchange Potential model, which attempts to explain the interactions between nucleons and the forces involved.
  • Concerns are raised about the absence of certain particles, such as pions, in some theoretical models.

Areas of Agreement / Disagreement

Participants express a range of views on the nature of binding energy, the contributions to hadron mass, and the mechanisms behind nucleon interactions. No consensus is reached on the fundamental reasons for the repulsive forces at short distances or the implications of negative binding energy.

Contextual Notes

Participants highlight the complexity of quark masses, distinguishing between current and constituent quark masses, and note that the discussion involves unresolved aspects of nuclear interactions and theoretical models.

americanforest
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Why are Hadrons so much heavier than their quark components? For example, the components of the proton have a combined mass of 12 MeV but the proton is ~950 MeV. If we look at binding energy:

[tex]B=\sum{m_{components}}-m_{whole}[/tex] so the Binding Energy must be a large negative number. Is this right? If so, why?
 
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Yes its right. It would take that much energy to separate them.
 
In Nuclear Physics [tex]m_{whole}\leq\sum{m_{components}}[/tex] correct? So in this case it is the other way around. What is the significance of that?

To put it more succinctly: What does it mean to have a negative Binding Energy?
 
In a hydrogen atom, the mass is equal to the mass of the proton plus the mass of the electron plus the mass of the energy stored in the electromagnetic field, less the binding energy.

For the hydrogen atom, the energy stored in the electromagnetic field is tiny - parts per million. For a proton, the energy stored in the gluon field is huge: 99% of the mass of the proton.
 
americanforest said:
Why are Hadrons so much heavier than their quark components? For example, the components of the proton have a combined mass of 12 MeV but the proton is ~950 MeV. If we look at binding energy:

[tex]B=\sum{m_{components}}-m_{whole}[/tex] so the Binding Energy must be a large negative number. Is this right? If so, why?

Well the case of the nucleus mass being smaller then the constituent nuclei is indeed due to the negative binding energy. This is shown by the semi-empirical mass formula. The nucleon-nucleon potential becomes repulsive at very short distances.

Inside the nucleon things are totally different though :

The sum of the constituent quarkmasses is much smaller then the mass of the hadron. The extra mass comes from the potential and kinetic energy of the quarks and also from dynamical quarks.

For example the proton contains three valence quarks of three different colours (red, green and blue), but it also contains dynamical (sea) quarks. These are quark-antiquark pairs that appear and disappear through energy fluctuations in the vacuum.

These dynamical quarkpairs will generate mass. The mass of a hadron is bigger then the sum of the masses of the constituent quarks (the three quarks of the proton). But the dynamical quarks also generate mass (via symmetry breaking) , so in the end the mass of a proton is BIGGER then the sum of the three quark masses.


marlon
 
Hi,

as you noted correctly, the mass default calculated as such is negative. In principle, we imagine that separating them would produce energy.

However, this mass default has no physical meaning, because quarks are premanently confined. Therefore, you can not interpret you result as the stored potential energy. There is no "asymptotic state at infinity" to perform the difference.

In addition, you must be careful when you talk about quark masses. There are current quark masses appearing in the lagrangian, and hose are (I think) the one you quote. Basically what you do is that you use symetries to find relation between ratios of different masses (quarks and hadrons). And there are constituent quark masses which are used in various models of bound states.

An intriguing possibility is that the naked current quark mass measured at high energy is really the same at the constituent quark mass, but renomalized at a lower energy. This is not an easy topic however.
 
marlon said:
Well the case of the nucleus mass being smaller then the constituent nuclei is indeed due to the negative binding energy. This is shown by the semi-empirical mass formula. The nucleon-nucleon potential becomes repulsive at very short distances.

Hi,

do we explain why nucleon-nucleon potential becomes repulsive at very short distances ?
Or is it only phenomenologic ?
 
Barmecides said:
do we explain why nucleon-nucleon potential becomes repulsive at very short distances ?
Or is it only phenomenologic ?
Did you try to compare nuclei/nucleon radii ? It is a quite interesting game :biggrin:
 
Barmecides said:
Hi,

do we explain why nucleon-nucleon potential becomes repulsive at very short distances ?
Or is it only phenomenologic ?

the most fundamental reason I can give you is the Pauli principle. In comparison, you can't put two atoms to close to each other.
 
  • #10
Thanks,

I found some interesting information on wikipedia : http://en.wikipedia.org/wiki/Internucleon_interaction
but they do not explain shot distance repealing.
Pauli principle should not exclude having two nucleons with opposite spins at the same position.
They were not talking about nucleon/nucleii radii.
 
  • #11
no but what is considered are the quarks that builds up the nucleons.
 
  • #12
Barmecides said:
Pauli principle should not exclude having two nucleons with opposite spins at the same position.
I think we are oversimplifying here. You don't need spin for Pauli principle not to exclude two nucleons at the same positions. They just can have different momenta.

In addition, isospin comes into game as well, and nucleons in a nuclei do form pairs indeed.
 
  • #13
humanino said:
I think we are oversimplifying here. You don't need spin for Pauli principle not to exclude two nucleons at the same positions. They just can have different momenta.

In addition, isospin comes into game as well, and nucleons in a nuclei do form pairs indeed.

Spin or isospin, the question remains : where this short repulsive force is coming from ?
 
  • #14
Barmecides said:
Spin or isospin, the question remains : where this short repulsive force is coming from ?
Nobody knows ! And it is very interesting :smile:

Now, if you have pairing, very grosso-modo, you have two nucleons at the same position with opposite momenta (reminds you of BCS model of superconductivity ?). This situation is dubbed "short-range correlation". It is very well observed. It implies that nucleons are going to behave just as if they were repelling at short distances (but really, they are so much attracted to each other that they form a bosonic pair !).

Another model : One Boson Exchange Potential "phenomenological" models. You have a light scalar and isoscalar sigma meson for long range attraction, and a heavier omega isoscalar vector meson for repulsion. You also put in a rho isovector vector for isospin dependent effects. All is great, you have a relativistic mean field theory of the nuclear structure. But wait ! Where are the pions ? What is this sigma !?
 
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  • #15
humanino said:
Another model : One Boson Exchange Potential "phenomenological" models. You have a light scalar and isoscalar sigma meson for long range attraction, and a heavier omega isoscalar vector meson for repulsion. You also put in a rho isovector vector for isospin dependent effects. All is great, you have a relativistic mean field theory of the nuclear structure. But wait ! Where are the pions ? What is this sigma !?

Thanks ! That model looks interesting.
Hope some day nuclear physicists can run a big simulation with Lattice QCD to check 2 nucleous hypothesis.
 

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