Why Are Relative Velocities in Elastic Collisions Frame-Independent?

Click For Summary
Relative velocities in elastic collisions remain constant across different inertial reference frames due to the conservation of momentum and kinetic energy. The concept of "relatively inertial reference frames" refers to frames that do not accelerate relative to each other, ensuring consistent measurements of velocity. The discussion highlights the need for a mathematical understanding of these principles, particularly in the context of two-particle interactions. It emphasizes that if momentum is conserved in one frame, it is conserved in all inertial frames, leading to unchanged relative velocities before and after collisions. Overall, the principles of elastic collisions are frame-independent, reinforcing the foundational concepts of physics.
gibberingmouther
Messages
120
Reaction score
15

Homework Statement


"For a two-particle interaction, the relative velocity between the two vectors is independent of the choice of relatively inertial reference frames."
and
"The change in kinetic energy is independent of the choice of relatively inertial reference frames."

My textbook says that if you look at the velocities of a two particle elastic interaction before and after the collision, regardless of which reference frame you choose, the relative velocities before and after will be the same. It just says this, and I guess expects you to make an intuitive leap? I wanted a more mathematical explanation which is why i looked on the internet and found the MIT page. The professor gives an example in the case of a two particle interaction where the one particle is twice the mass of the other, and shows that in this case the relative velocities will be the same. Cool, but i wasn't really satisfied.

Anyway, besides hoping for a better explanation of the relative velocities in an elastic collision, I was also confused by the terminology of "a relatively inertial reference frame". I want to read and understand the MIT pdf but i need to be able to know what that terminology means first. I am also hoping someone could help me by explaining the two statements from the pdf i quoted above.

http://web.mit.edu/8.01t/www/materials/modules/chapter15.pdf

Homework Equations



conservation of kinetic energy and conservation of momentum.

The Attempt at a Solution



i tried to imagine two coordinate systems moving relative to each other and the velocities being different while the relative velocities are the same. couldn't quite manage it. maybe i should drink more coffee, lol? I'm grateful for my intelligence but I'm not quite an Einstein :(

i was able to read some of the math in the MIT pdf but still trudging through, just need to get unstuck on the parts i mentioned above.
 
Physics news on Phys.org
gibberingmouther said:
two coordinate systems moving relative to each other and the velocities being different while the relative velocities are the same.
If in the first frame the velocities are ##\vec u_1## for particle 1 and ##\vec u_2## for particle 2, what is the velocity of particle 2 relative to particle 1 in that frame?
If a second frame has velocity ##\vec f## relative to the first frame, what is the velocity of particle 1 in that frame?
Likewise, particle 2 in the second frame?
gibberingmouther said:
relatively inertial reference frame"
I believe that means the frames are not accelerating relative to each other. So they need not be inertial franes, but whatever acceleration they have is the same for each.
 
  • Like
Likes gibberingmouther
The easiest way of seeing that the relative velocity must remain the same after the collision is to go to the centre of mass frame where the total momentum is zero. This means that both objects must have momenta that are equal in magnitude but opposite in direction.
 
gibberingmouther said:
"The change in kinetic energy is independent of the choice of relatively inertial reference frames."

It looks like you have actually several questions here.

1) It might be a good exercise to show that if momentum is conserved in one inertial frame of reference, then it is conserved in all inertial frames of reference.

Hint: use the idea @haruspex gave you above for 3D motion.

2) Then, you might like to show that if momentum is conserved, then the change in kinetic energy is the same in all inertial reference frames.

Hint: try the case of 1D motion first and then extrapolate to 3D.

The above is true for any interaction of two or more particles.

3) A collision of two particles is elastic if kinetic energy is conserved, which is equivalent to the separation speed between the particles being the same before and after the collision.

Again, it's a good exercise to show this. Hint: see @Orodruin 's post.
 
Last edited:
gibberingmouther said:
I wanted a more mathematical explanation which is why i looked on the internet and found the MIT page.

The maths is there on page 15_6 of your very excellent reference.
 
  • Like
Likes gibberingmouther
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K