Why Are These Accretion Disk Concepts Challenging?

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Shan K
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I was studying about Accretion disks and found some difficulties regarding some concepts. My questions are

1. For an accretion disk, ## v_r<<c_s ## Why?
2. The conservation of mass equation is derived as,


The mass in an annulus of radius ##\Delta r## is ##2\pi r \Delta r\Sigma ## and it is changing due to the mismatch of mass outflow and inflow which is written as,

$$ \frac{\partial}{\partial t}(2πr\Delta r\Sigma) = v_r(r,t)2πr\Sigma(r,t)−v_r(r+\Delta r,t)2π(r+\Delta r)\Sigma(r+\Delta r,t)\\ \approx-2\pi\Delta r\frac{\partial (r\Sigma v_r)}{\partial r} $$

up to this I have no problem but it further says that this equation in the ## \Delta r\rightarrow0 ## limit gives,

$$r\frac{\partial\Sigma}{\partial t}+\frac{\partial (r\Sigma v_r)}{\partial r}=0$$

and I can't able to derive how that limit gives that equation.

3. The angular momentum conservation equation is derived from the Navier-Stokes equation as,
$$ \frac{\partial \vec{v}}{\partial t}+(\vec{v}.\vec{\nabla})\vec{v}=-\frac{1}{\rho}(\vec{\nabla}P-\vec{\nabla}.\sigma)-\vec{\nabla}\Phi $$

In the axisymmetry assumption and no momentum loss or gain from the ## z ## direction one gets,

$$\Sigma\Big(\frac{\partial v_\phi}{\partial t}+\frac{v_rv_\phi}{r}+v_r\frac{\partial v_\phi}{\partial r}\Big)=\frac{1}{r^2}\frac{\partial}{\partial r}(r^2 T_{r\phi}) $$

Now my question is, shouldn't the RHS be ## \frac{1}{r}\frac{\partial}{\partial r}(r T_{r\phi}) ## instead of ## \frac{1}{r^2}\frac{\partial}{\partial r}(r^2 T_{r\phi}) ## because the ## r ## part of ## \vec{\nabla}.\vec{f}## in the cylindrical coordinate is ## \frac{1}{r}\frac{\partial}{\partial r}(r f_r) ##.

Thanks in advance..
 
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Can you post the source. I like to check the authors definition of each symbol.

Shan K said:
up to this I have no problem but it further says that this equation in the ## \Delta r\rightarrow0 ## limit gives,

$$r\frac{\partial\Sigma}{\partial t}+\frac{\partial (r\Sigma v_r)}{\partial r}=0$$

and I can't able to derive how that limit gives that equation.

∇r is the "size" of the annulus?? The physical manifestation of that limit could be stated as "if the accretion disc becomes more like a ring or planet". There is no viscous laminar flow if the annulus has no area. could conclude that the mass loss is 0.

Shan K said:
$$ \frac{\partial}{\partial t}(2πr\Delta r\Sigma) = v_r(r,t)2πr\Sigma(r,t)−v_r(r+\Delta r,t)2π(r+\Delta r)\Sigma(r+\Delta r,t)\\ \approx-2\pi\Delta r\frac{\partial (r\Sigma v_r)}{\partial r} $$

up to this I have no problem but it further says that this equation in the ## \Delta r\rightarrow0 ## l
For a generic f(x) = a-b
limitb→a f(x)⇒0

Shan K said:
1. For an accretion disk, ## v_r<<c_s ## Why?

Is that saying the "turbulent velocity is much lower than the speed of sound"? Would be scary if that were no true. Storms on Earth would be quite intense.
 
stefan r said:
Can you post the source. I like to check the authors definition of each symbol.
See the attachment I can not understand how to derive equation (2.4) from (2.3).
stefan r said:
Is that saying the "turbulent velocity is much lower than the speed of sound"? Would be scary if that were no true. Storms on Earth would be quite intense.
##v_r## is the radial velocity of the gas in the accretion disk and ##c_s## is the sound speed.
 

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