Why Do Cosine and Sine Give Different Angles for the Same Vector?

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SUMMARY

The discussion centers on the calculation of angles for the vector a = (3, -3) using trigonometric functions. The magnitude of the vector is determined to be ||a|| = 3√2. The angle calculated using cosine, θ = 45 degrees, is inconsistent with the angle derived from sine, which results in θ = 315 degrees. This discrepancy arises because arccos returns angles between 0 and 180 degrees, while arcsin returns angles between -90 and +90 degrees, necessitating the use of the correct quadrant for accurate angle representation.

PREREQUISITES
  • Understanding of vector magnitude and direction
  • Knowledge of trigonometric functions: sine and cosine
  • Familiarity with the unit circle and angle measurement
  • Concept of quadrants in the Cartesian plane
NEXT STEPS
  • Study the unit circle and its application in trigonometry
  • Learn about the properties of arccos and arcsin functions
  • Explore vector representation in different quadrants
  • Investigate the relationship between sine, cosine, and tangent in angle calculations
USEFUL FOR

Students studying trigonometry, mathematics educators, and anyone interested in understanding vector analysis and angle calculations in the Cartesian coordinate system.

k_squared
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Homework Statement



Find the magnitude of a and the smallest positive angle theta from the positive x-axis to the vector OP that corrosponds to a.

a= (3,-3)

Homework Equations



a1 = ||a|| * cos theta
a2 = ||a|| * sin theta
3. The Attempt at a Solution

||a|| = [tex]\sqrt{}[/tex](9+9) = 3[tex]\sqrt{}[/tex]2
a1 = 3[tex]\sqrt{}[/tex]2 * cos theta

=1/[tex]\sqrt{}[/tex]2 =acos = 45 degrees.

However doing the other side of the equation...

a2= -1/[tex]\sqrt{}[/tex]2 = asin = -45 degrees = 315 degrees, which is the right answer. I thought they were supposed to be consistent...
 
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k_squared said:

Homework Statement



Find the magnitude of a and the smallest positive angle theta from the positive x-axis to the vector OP that corrosponds to a.

a= (3,-3)

Homework Equations



a1 = ||a|| * cos theta
a2 = ||a|| * sin theta
3. The Attempt at a Solution

||a|| = [tex]\sqrt{}[/tex](9+9) = 3[tex]\sqrt{}[/tex]2
a1 = 3[tex]\sqrt{}[/tex]2 * cos theta

=1/[tex]\sqrt{}[/tex]2 =acos = 45 degrees.

However doing the other side of the equation...

a2= -1/[tex]\sqrt{}[/tex]2 = asin = -45 degrees = 315 degrees, which is the right answer. I thought they were supposed to be consistent...
arccos produces an angle between 0 and 180 degrees, while arcsin produces an angle between -90 and + 90 degrees. Since your vector is in the fourth quadrant, an angle of 45 degrees wouldn't be right, nor would -45 degrees, since the problem asks for a positive angle.
 

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